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stich3 [128]
3 years ago
11

A package of crackers weighing 8.2 Oz cost $2.87 what is the cost per ounce of the crackers

Mathematics
1 answer:
ololo11 [35]3 years ago
7 0
All you have to do is divide.

When you divide you get $0.35
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Which is the 8th term of th geometric sequence 1024,256,64,...?
Elenna [48]
The eighth term is 0.0625 
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3 years ago
P105a06.sas are the same statistics in the report and data? what do the first 5 rows in the data represent?
ehidna [41]

Since P105a06.sas are the same statistics in the given report and data for this lab, we can infer and logically deduce that the first 5 rows in the data means the statistics are different.

<h3>What is SAS?</h3>

SAS is an abbreviation for Statistical Analysis System and it can be defined as a statistical software suite which was developed at North Carolina State University by SAS Institute for the following field of study:

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Since it has been stated that P105a06.sas are the same statistics in the given report and data for this lab, we can infer and logically deduce that the first 5 rows in the data means the statistics are different.

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7 0
1 year ago
Solve the equation for y.<br> 8x – 9y = 11
pav-90 [236]
8x-9y=11

First you move the 8x because you have to leave the 9y alone

8x-9y=11
-8x        -8x

-9y=11-8x

Now you have to move the -9, so the inverse of multiplying is dividing so you divide -9.

-9y/-9= 11/-9 -8x/-9

since you can't have negative as a denominator it would be:

y= -11/9+8x/9

<span>You have to change the signs</span>
3 0
3 years ago
An example problem in a Statistics textbook asked to find the probability of dying when making a skydiving jump.
MArishka [77]

Answer:

(a) 0.999664

(b) 15052

Step-by-step explanation:

From the given data of recent years,  there were about 3,000,000 skydiving jumps and 21 of them resulted in deaths.

So, the probability of death is \frac{21}{3000000}==0.000007.

Assuming, this probability holds true for each skydiving and does not change in the present time.

So, as every skydiving is an independent event having a fixed probability of dying and there are only two possibilities, the diver will either die or survive, so, all skydiving can be regarded as is Bernoulli's trial.

Denoting the probability of dying in a single jump by q.

q=7\times 10^{-6}=0.000007.

So, the probability of survive, p=1-q

\Rightarrow p=1-7\times 10^{-6}=0.999993.

(a) The total number of jump he made, n=48

Using Bernoulli's equation, the probability of surviving in exactly 48 jumps (r=48) out of 48 jumps (n=48) is

=\binom(n,r)p^rq^{n-r}

=\binom(48,48)(0.999993)^{48}(0.000007)^{48-48}

=(0.999993)^{48}=0.999664 (approx)

So, the probability of survive in 48 skydiving is 0.999664,

(b) The given probability of surviving =90%=0.9

Let, total n skydiving jumps required to meet the surviving probability of 0.9.

So, By using Bernoulli's equation,

0.9=\binom {n }{r} p^rq^{n-r}

Here, r=n.

\Rightarrow 0.9=\binom{n}{n}p^nq^{n-n}

\Rightarrow 0.9=p^n

\Rightarrow 0.9=(0.999993)^n

\Rightarrow \ln(0.9)=n\ln(0.999993) [ taking \log_e both sides]

\Rightarrow n=\frac {\ln(0.9)}{\ln(0.999993)}

\Rightarrow n=15051.45

The number of diving cant be a fractional value, so bound it to the upper integral value.

Hence, the total number of skydiving required to meet the 90% probability of surviving is 15052.

3 0
3 years ago
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