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vredina [299]
3 years ago
10

What is the general form of the equation of the line shown?

Mathematics
2 answers:
mario62 [17]3 years ago
8 0

Point/slope form is:-

y - y1 = m(x - x1) where m = slope and (x1, y1) is a point on the line

In the above diagram the slope is -1 and one point on the line is (0, -2) so we have:-

y - (-2) = -1(x - 0)

y + 2 = -x

x + y + 2 = 0 is the answer

igor_vitrenko [27]3 years ago
7 0

Answer:

x + y + 2 = 0 is the answer


Step-by-step explanation:

Point/slope form is:-


y - y1 = m(x - x1) where m = slope and (x1, y1) is a point on the line


In the above diagram the slope is -1 and one point on the line is (0, -2) so we have:-


y - (-2) = -1(x - 0)


y + 2 = -x


x + y + 2 = 0 is the answer



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