Question

What is the general form of the equation of the line shown?

Answer 1

Point/slope form is:-

y - y1 = m(x - x1) where m = slope and (x1, y1) is a point on the line

In the above diagram the slope is -1 and one point on the line is (0, -2) so we have:-

y - (-2) = -1(x - 0)

y + 2 = -x

x + y + 2 = 0 is the answer

Answer 2

Answer:

x + y + 2 = 0 is the answer

Step-by-step explanation:

Point/slope form is:-

y - y1 = m(x - x1) where m = slope and (x1, y1) is a point on the line

In the above diagram the slope is -1 and one point on the line is (0, -2) so we have:-

y - (-2) = -1(x - 0)

y + 2 = -x

x + y + 2 = 0 is the answer