Question

A bag contains one red one yellow one blue and one green marble what is the probability of choosing a green marble not replacing it and then choosing a red marble

Answer 1

The total probability of choosing a green marble not replacing it and then choosing a red marble is $\frac{1}{12}$

Solution:

Given that bag contains one red one yellow one blue and one green marble

To find: Probability of choosing a green marble not replacing it and then choosing a red marble

The probability of an event is given as:

$\text{ probability } =\frac{\text { number of favorable outcomes }}{\text { total number of possible outcomes }}$

Here total number of possible outcomes = 1 red + 1 yellow + 1 blue + 1 green

total number of possible outcomes = 4 marbles

Here favourable outcome is choosing a green marble not replacing it and then choosing a red marble

Let us first find probability of choosing a green marble

Favorable outcome = green marble

Number of favorable outcomes = 1

$probability = \frac{1}{4}$

Now without replacing, we have to choose a red marble

Without replacing means, green marble is not considered

So total number of possible outcomes = 4 - 1 = 3

$probability = \frac{1}{3}$

The total probability of choosing a green marble not replacing it and then choosing a red marble:

$\rightarrow \frac{1}{4} \times \frac{1}{3} = \frac{1}{12}$

So the required probability is $\frac{1}{12}$

Answer 2

Answer:B) 1/12♡

Step-by-step explanation: