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Alecsey [184]
1 year ago
12

Please help these are review questions for my test tomorrow and i cannot figure them out on my own

Mathematics
1 answer:
igomit [66]1 year ago
7 0

Answer:

17.A 18.A

Step-by-step explanation:

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Someone help me ( view picture below )
oksano4ka [1.4K]

Answer:

D. 13

Step-by-step explanation:

x = 5

2 x 5 + 3 = 13

5 + 8 = 13

meaning the side length has to be 13, also.

5 0
3 years ago
What is the equation of this graphed line ?
yanalaym [24]
Equations of straight lines are in the form y = mx + c (m and c are numbers). m is the gradient of the line and c is the y-intercept (where the graph crosses the y-axis).
7 0
3 years ago
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Angle XYZ is rotated 270 degrees counterclockwise about the origin to form angle X’Y’Z’. Which statement shows the measure of an
Kruka [31]
Hi i a doing the same thing and i have the answer as a hope this helps
6 0
3 years ago
PLEASE PEOPLE, HELP ME!! Geometry
Oksanka [162]
I use the sin rule to find the area

A=(1/2)a*b*sin(∡ab)

1) A=(1/2)*(AB)*(BC)*sin(∡B)
sin(∡B)=[2*A]/[(AB)*(BC)]

we know that
A=5√3
BC=4
AB=5
then

sin(∡B)=[2*5√3]/[(5)*(4)]=10√3/20=√3/2
(∡B)=arc sin (√3/2)= 60°

 now i use the the Law of Cosines 

c2 = a2 + b2 − 2ab cos(C)

AC²=AB²+BC²-2AB*BC*cos (∡B)

AC²=5²+4²-2*(5)*(4)*cos (60)----------- > 25+16-40*(1/2)=21

AC=√21= 4.58 cms

the answer part 1) is 4.58 cms

2) we know that

a/sinA=b/sin B=c/sinC

and

∡K=α

∡M=β

ME=b

then

b/sin(α)=KE/sin(β)=KM/sin(180-(α+β))

KE=b*sin(β)/sin(α)

A=(1/2)*(ME)*(KE)*sin(180-(α+β))

sin(180-(α+β))=sin(α+β)

A=(1/2)*(b)*(b*sin(β)/sin(α))*sin(α+β)=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

KE/sin(β)=KM/sin(180-(α+β))

KM=(KE/sin(β))*sin(180-(α+β))--------- > KM=(KE/sin(β))*sin(α+β)

the answers part 2) are

side KE=b*sin(β)/sin(α)
side KM=(KE/sin(β))*sin(α+β)
Area A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

5 0
3 years ago
I need help on this I am just going to use the picture
Radda [10]

Answer:

D

Step-by-step explanation:

let y = f(x), that is

y = \frac{2x-3}{5}

Rearrange making x the subject

Multiply both sides by 5

5y = 2x - 3 ( add 3 to both sides )

5y + 3 = 2x (divide both sides by 2 ) , then

x = \frac{5y+3}{2}

Change y back into term of x, hence

f^{-1}(x) = \frac{5x+3}{2} → D

4 0
3 years ago
Read 2 more answers
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