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2 years ago

Tonya wrote the equation below which solves for x

Mathematics

1 answer:

s2008m [1.1K]2 years ago

8 0

can you put the picture or answers to choose from

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I need help ASAP due rn!

coldgirl [10]

There are no real solutions

5 0

3 years ago

The movie theater sold 50 buckets of popcorn last Wednesday. 60 people watched movies that day, and 40 of those people ate popco

STALIN [3.7K]

Answer:

Step-by-step explanation:

60/40Ⅹ50=70

I hope this helps

3 0

2 years ago

Help me ASAP please and I hate math

xxMikexx [17]

The answer is y is greater y > -8

7 0

2 years ago

Read 2 more answers

The table shows the height of 5 students in inches what is the mean absolute deviation for these numbers

german

Answer:

Step-by-step explanation:

To find the mean absolute deviation (MAD), first find the mean (or average).

μ = (59 + 71 + 68 + 75 + 67) / 5

μ = 68

Next, subtract the mean from each value and take the absolute value.

|59 − 68| = 9

|71 − 68| = 3

|68 − 68| = 0

|75 − 68| = 7

|67 − 68| = 1

Sum the results and divide by the number of students.

MAD = (9 + 3 + 0 + 7 + 1) / 5

MAD = 4

3 0

3 years ago

If a/b < c/d with b > 0, d > 0, prove that a+c / b+d lies between the two fractions a/b and c/d .

Tems11 [23]

Divide through everything by b :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ab + \dfrac cb}{1 + \dfrac db}$

Since a/b < c/d, it follows that

$\dfrac{a+c}{b+d} < \dfrac{\dfrac cd+\dfrac cb}{1 + \dfrac db}$

Multiply through everything on the right side by b/d to get

$\dfrac{a+c}{b+d} < \dfrac{\dfrac{bc}{d^2}+\dfrac cd}{\dfrac bd+1} = \dfrac{\dfrac cd\left(\dfrac bd+1\right)}{\dfrac bd+1} = \dfrac cd$

and so (a + c)/(b + d) < c/d.

For the other side, you can do something similar and divide through everything by d :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ad + \dfrac cd}{\dfrac bd + 1}$

and a/b < c/d tells us that

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ad + \dfrac ab}{\dfrac bd + 1}$

Then

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ab + \dfrac{ad}{b^2}}{1 + \dfrac db} = \dfrac{\dfrac ab\left(1+\dfrac db\right)}{1 + \dfrac db} = \dfrac ab$

and so (a + c)/(b + d) > a/b.

Then together we get the desired inequality.

5 0

2 years ago