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vovangra [49]
1 year ago
14

Determine whether each order pair is a solution of the equation

Mathematics
1 answer:
Harman [31]1 year ago
3 0

Answer:

Given equation is, x+3y=6

To determine whether each order pair is a solution of the equation

(3,1)

we have that, when x=3 we get y=1

Let us check this in the equation.

Put x=3, we get

3+3y=6\begin{gathered} 3y=6-3 \\ 3y=3 \end{gathered}y=1

Hence (3,1) is the solution of the equation.

(6,0)

Put x=6, we get,

6+3y=6y=0

Hence (6,0) is the solution of the equation.

(-2,2/3)

Put x=-2, we get,

-2+3y=6

3y=6+2

y=\frac{8}{3}

Hence (-2,2/3) is not the solution of the equation.

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The initial price of buzz stock is $20 per share. After 20 days the stock price is $30 per share and after 40 days the price is
Temka [501]

Answer:

s(t) = -\dfrac{t^2}{160}+\dfrac{5}{8}t+20

Step-by-step explanation:

given,

initial price of buzz stock = $ 20 per share

after 20 days

stock price = $30 per share

after 40 days

the price =  $35 per share

let say it is modeled by

y = ax² + b x + c

x = number of days

y = stock price

x = 0 y = 20

20 = a x 0 + b x 0 + c

c = 20

x = 20 y = 30

30 = 20² a + 20 b + 20

400 a + 20 b = 10...........(1)

x = 40 y = 35

35 = 40² a + 40 b + 20

1600 a + 40 b = 15...........(2)

solving equation (1)and (2)

a = - 1/160

b = 5/8

y = -\dfrac{x^2}{160}+\dfrac{5}{8}x+20

s(t) = -\dfrac{t^2}{160}+\dfrac{5}{8}t+20

hence , the above equation is multipart function

5 0
3 years ago
Pleksndkdndjdndnbrksndkdbmdbdksbdkxndjndkzms help
sladkih [1.3K]

Answer:

2 x 10^1 (it looks weird how i typed it so its the first answer btw)

Step-by-step explanation:

(6.4 x 10^3) / (3.2 x 10^2)     1. Follow PEMDAS

(6400) / (320)                      2. Divide regularly

20                                        3.  Take the 20 and put it in scientific notation

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hope this helps :)           

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Answer:

Step-by-step explanation:

       Location    Reflect over x              Reflect over y

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