The greatest common factor is the biggest number taken from the values.
Q1. The answer is <span>A. 5y^6
</span>

Since

, then

Back to our expression:

The greatest common factor is thus

Q2. The answer is <span>D. 12xy^2
</span>

We will use the rule

to factorise the exponents:

The greatest common factor is thus
Answer:
The monthly fee would be $23
Step-by-step explanation:
hope it helps mark as brainllest if help!!!
Answer:
CI = (98.11 , 98.49)
The value of 98.6°F suggests that this is significantly higher
Step-by-step explanation:
Data provided in the question:
sample size, n = 103
Mean temperature, μ = 98.3
°
Standard deviation, σ = 0.73
Degrees of freedom, df = n - 1 = 102
Now,
For Confidence level of 99%, and df = 102, the t-value = 2.62 [from the standard t table]
Therefore,
CI = 
Thus,
Lower limit of CI = 
or
Lower limit of CI = 
or
Lower limit of CI = 98.11
and,
Upper limit of CI = 
or
Upper limit of CI = 
or
Upper limit of CI = 98.49
Hence,
CI = (98.11 , 98.49)
The value of 98.6°F suggests that this is significantly higher and the mean temperature could very possibly be 98.6°F
I think the answer may be both. Sorry if it’s not