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marysya [2.9K]
1 year ago
9

Section 1.2

SAT
1 answer:
leonid [27]1 year ago
3 0

The option that is not a correct description of the distribution of the amount spent by the 50 shoppers at the grocery store is D) The distribution is uniform, with all values equally likely.

<h3>What is a stemplot?</h3>

A stemplot is a graphical way of displaying numerical data that uses place value to group the data. The leftmost digits of the data values form the stem, and the rightmost digits form the leaf.

The distribution is symmetric, because the left and right halves of the stemplot are roughly mirror images of each other. The mean and median are both about $25, because the middle value of the data is $25, and the sum of the data values divided by the number of data values is also $25. The distribution is not skewed to the right or left, because there are no long tails or outliers on either side of the peak.

Learn more about stemplot on:

brainly.com/question/11320163

#SPJ4

Complete question

The stemplot displays data on the amount spent by 50 shoppers at a grocery store. Note that the values have been rounded to the nearest dollar.

Which of the following is not a correct description of the distribution of the amount spent by the 50 shoppers at the grocery store?

A) The distribution is symmetric, with a mean and median of about $25. B) The distribution is skewed to the right, with a mean of about $30 and a median of about $25. C) The distribution is skewed to the left, with a mean of about $20 and a median of about $25. D) The distribution is uniform, with all values equally likely.

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<h3>What is a t-distribution confidence interval?</h3>

The confidence interval is:

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In which:

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The critical value, using a t-distribution calculator, for a two-tailed <em>95% confidence interval</em>, with 49 - 1 = <em>48 df</em>, is t = 2.0106.

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\overline{x} + t\frac{s}{\sqrt{n}} = 12.2 + 2.0106\frac{1.6}{\sqrt{49}} = 12.7

The 95% confidence interval for the number of units students in their college are enrolled in is (11.7, 12.7).

More can be learned about the t-distribution at brainly.com/question/16162795

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