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The magnitude of the force of the elevator floor on the person is; 807.13 N
<h3>What is the Magnitude of force? </h3>
We are given;
Weight; W = 0.7 KN
Acceleration; a = 1.5 m/s²
There are only two forces acting on the person: which are his weight W (downward) and the normal force N of the floor against the body (upward). Thus the equilibrium equation here is;
N - W = F
N - W = ma
Here, m is the mass of body, and its value is calculated as;
W = mg
0.7 = 9.81m
m = 0.7/9.81
m = 71.42 kg
Thus;
N - 0.7 = 71.42 * 1.5
N = 0.7 + (71.42 * 1.5)
N = 807.13 N
Read more about Magnitude of Force at; brainly.com/question/9056570
