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e-lub [12.9K]
1 year ago
14

Identify the set of X-values for which f(X) is greater than or equal to 0.

Mathematics
1 answer:
Allushta [10]1 year ago
6 0

The given function is greater than or equal to 0 for the interval given as follows:

{x | x ≤ -3 or -1 ≤ x ≤ 0 or x ≥ 2}.

<h3>When a function is positive and when it is negative?</h3>

  • A function is positive when it is above the x-axis.
  • A function is negative when it is below the x-axis.

For this problem, with a closed interval, we have that the function is above for:

x ≤ -3, -1 ≤ x ≤ 0, x ≥ 2.

Hence the interval notation is:

{x | x ≤ -3 or -1 ≤ x ≤ 0 or x ≥ 2}.

More can be learned about functions at brainly.com/question/24808124

#SPJ1

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Answer:

5 years and 5 months

Step-by-step explanation:

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<u>Compound Interest Formula</u>

\large \text{$ \sf A=P(1+\frac{r}{n})^{nt} $}

where:

  • A = final amount
  • P = principal amount
  • r = interest rate (in decimal form)
  • n = number of times interest applied per time period
  • t = number of time periods elapsed

Given:

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Substitute the given values into the formula and solve for t:

\implies \sf 17474=7790\left(1+\dfrac{0.15}{12}\right)^{12t}

\implies \sf \dfrac{17474}{7790}=\left(1.0125}\right)^{12t}

\implies \sf \ln\left(\dfrac{17474}{7790}\right)=\ln \left(1.0125}\right)^{12t}

\implies \sf \ln\left(\dfrac{17474}{7790}\right)=12t \ln \left(1.0125}\right)

\implies \sf t=\dfrac{\ln\left(\frac{17474}{7790}\right)}{12 \ln \left(1.0125}\right)}

\implies \sf t=5.419413037...\:years

Therefore, the money was in the account for 5 years and 5 months (to the nearest month).

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Answer:

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Answer:

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Which operation results in a binomial? (3y ^ 6 + 4) (9y ^ 12 - 12y ^ 6 + 16)
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Step-by-step explanation:

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From the gotten value, it can be seen that the resulting answer produces 3 terms, showing that it results in a trinomial instead of binomial.

Using a plus (-) sign to check:

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<em>Hence none of the operations given results in a binomial</em>

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