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Kryger [21]
1 year ago
4

Yumi takes 5/12 hour to complete 50 math problems Eric is able to complete 48 math problems in 2/5 hour which student can comple

te math problems at a greater rate of problems per hour
Mathematics
1 answer:
Rudik [331]1 year ago
8 0

If Yumi takes 5/12 hour to complete 50 math problems Eric is able to complete 48 math problems in 2/5 hour the student that can complete math problems at a greater rate of problems per hour is: They solve the same number of problems per hour.

<h3>Rate</h3>

Calculation for the rate of Yumi

Yumi=5/12×60

Yumi=25 minutes

Rate=50/25

Rate=2

Calculation for the rate of Eric

Eric=2/5×60

Eric=24 minutes

Rate=48/24

Rate=2

Hence, Both Yumi and Eric has the same rate which is 2.


Therefore If Yumi takes 5/12 hour to complete 50 math problems Eric is able to complete 48 math problems in 2/5 hour the student that can complete math problems at a greater rate of problems per hour is: They solve the same number of problems per hour.

Learn more about rate here: brainly.com/question/11416162

#SPJ1

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Answer:

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Step-by-step explanation:

In the 30°-60°-90° triangle, there is a ratio between its sides

side opp (30°) : side opp (60°) : hypotenuse

       1               :         \sqrt{3}            :        2

In the given triangle

∵ The side opposite to 30° is s

∵ The side opposite to 60° is q

∵ The hypotenuse is 8

→ Use the ratio above to find the lengths of s and q

side opp (30°) : side opp (60°) : hypotenuse

       1               :         \sqrt{3}            :        2

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∴ The length of q is 4\sqrt{3}

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