Answer: The 2nd one on your right
Step-by-step explanation:
The equation
can be used to find the measure of ∠BAC ⇒ 2nd answer
Step-by-step explanation:
Let us revise the trigonometry ratios in the right triangle ABC, where B is the right angle, AC is the hypotenuse, AB and BC are the legs of the triangle
The trigonometry ratios of the ∠BAC, the opposite side to this angle is BC and the adjacent side to it is AB are
In Δ ABC
∵ ∠ BCA is a right angle
∴ The hypotenuse is AB
∵ The adjacent side to ∠CAB is AC
∵ The opposite side to ∠CAB is BC
∵ AB = 13 units ⇒ hypotenuse
∵ CB = 12 units ⇒ opposite
∵ AC = 5 units ⇒ adjacent
- Let us find the trigonometry ratios of angle BAC
∵ m∠CAB is x
∵ ![sin(x)=\frac{BC}{AB}](https://tex.z-dn.net/?f=sin%28x%29%3D%5Cfrac%7BBC%7D%7BAB%7D)
∴ ![sin(x)=\frac{12}{13}](https://tex.z-dn.net/?f=sin%28x%29%3D%5Cfrac%7B12%7D%7B13%7D)
∴ ![x=sin^{-1}(\frac{12}{13})](https://tex.z-dn.net/?f=x%3Dsin%5E%7B-1%7D%28%5Cfrac%7B12%7D%7B13%7D%29)
∵
∴ ![cos(x)=\frac{5}{13}](https://tex.z-dn.net/?f=cos%28x%29%3D%5Cfrac%7B5%7D%7B13%7D)
∴ ![x=cos^{-1}(\frac{5}{13})](https://tex.z-dn.net/?f=x%3Dcos%5E%7B-1%7D%28%5Cfrac%7B5%7D%7B13%7D%29)
∵
∴
∴ ![x=tan^{-1}(\frac{12}{5})](https://tex.z-dn.net/?f=x%3Dtan%5E%7B-1%7D%28%5Cfrac%7B12%7D%7B5%7D%29)
The equation
can be used to find the measure of ∠BAC
Learn more:
You can learn more about the trigonometry ratios in brainly.com/question/4924817
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X < -3. Subtract one from both sides and you get x + 8 over 5 is less than 1. Multiple both sides by 5 and you get x + 8 is less than 5. Finally, subtract 8 from both sides and you get x is less than -3.
Answer:
Ratio = 5/3
The ratio (larger to smaller) of the perimeters is 5/3
Step-by-step explanation:
Attached is an image of the two triangles.
Since both triangles are similar, the ratio of their perimeter is equal to the ratio of each similar sides.
Ratio = P1/P2 = S1/S2
Similar side for triangle 1 S1 = 15ft
Similar side for triangle 2 S2 = 9ft
Substituting the values;
Ratio = 15ft/9ft = 5/3
Ratio = 5/3
The ratio (larger to smaller) of the perimeters is 5/3