There are 48 ways to do this.
We will have 7 identical chairs around the table.
<span>We need to seat Pierre, Rosa and Thomas so that no two of them are together. This basically means alternating them between the other people at the table. Let Pierre sit first. Each seat is identical so he sits in one way. Now each seat is distinct relative to Pierre. There are 4 seats identified for the other members of the group and 2 for the Rosa and Thomas. The 4 other members can occupy the 4 distinct seats in 4! ways and Rosa and Thomas can occupy the 2 distinct seats in 2! ways. This gives us 4!*2!=4(3)(2)(1)(2)(1)=48.</span>
6 + 21 = 27 (Add six ones)
60 + 21 = 81 (Add six tens)
I hope this helps:)
I'm sorry if it doesn't:(
Answer:
.35/100
Step-by-step explanation:
35 cents over 1.00
Can you post a better picture it looks a little blerry
Answer:
A. 8/10 divided by 8
Step-by-step explanation:
We just got it right on my son's quiz but we figured it out by:
- Multiplying both the numerator and denominator by 2.
