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HACTEHA [7]
3 years ago
11

ILL GIVE BRAINLIEST IM ON A TIME CRUNCH PLEASE HELP!!!!! What is the solution to the system of equations below? y = negative thr

ee-fourths x + 3 and y = –12
(20, –12)
(12, –12)
(–6, –12)
(–12, 12)
Mathematics
2 answers:
Vesnalui [34]3 years ago
6 0

Answer:

The system of equations as described:

y = (-3/4)x + 3

y = -12

Combining two equations, we have:

=> -12 = (-3/4)x + 3

=> -15 = (-3/4)x

=> x = -15 x (-4/3) = 20

=> Solution is (20, -12)

=> Option A is correct.

Hope this helps!

:)

saveliy_v [14]3 years ago
5 0

Step By Step:

The equations given to us are:

y = (-3/4)x + 3

y = -12

Now that we have y we can change that to -12

-12 = (-3/4)x + 3

-15 = (-3/4)x

x = -15 x (-4/3) = 20

This would give us (20, -12)

Answer

<h3> A. (20,-12)</h3>

Hope this helps

give brainliest if you please

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