Answer:
170 in^2
Step-by-step explanation:
you have to find the area of each surface of the square
1) the square on the right side:
5x5=25 in^2
there are 2 of these on opposite sides
2)the of the rectangle facing us;
6x5=30in^2 (5 because 5 is the height)
there are 4 of these
3)add up all the areas
25+25+30+30+30+30=170in^2
Answer:
1. Yes
∆RST ~ ∆WSX
by SAS
2. Yes
∆ABC ~ ∆PQR
by SSS
3. Yes
∆STU ~ ∆JPM
by SAS
4. Yes
∆DJK ~ ∆PZR
by SAS
5. Yes
∆RTU ~ ∆STL
by SAS
5. Yes
∆JKL ~ ∆XYW
by SAS
6. No
7. Yes
∆BEF ~ ∆NML
by SAS
8. Yes
∆GHI ~ ∆QRS
by SSS
9. x=22
10. x=12
Step-by-step explanation:
1. RS/WS=ST/SX and m<RST=m<WSX
2. AB/PQ=8/6=4/3
BC/QR=AC/PR=12/9=4/3
AB/PQ=BC/QR=AC/PR
3. ST/JP=10/15=2/3
SU/JM=14/21=2/3
ST/JP=2/3=SU/JM
and m<TSU=70°=m<PJM
4. DK/PR=8/4=2
JK/ZR=18/9=2
DK/PR=2=JK/ZR
and m<DKJ=65°=m<PRZ
5. RT/ST=UT/LT
and m<RTU=m<STL
6. KL/YW=20/18=10/9
JL/XW=36/24=3/2
KL/YW=10/9≠3/2=JL/XW
7. BF/NL=24/16=3/2
BE/NM=39/26=3/2
BF/NL=3/2=BE/NM
and m<EBF=m<MNL
8. GH/QR=32/20=8/5
HI/RS=40/25=8/5
GI/QS=24/15=8/5
GH/QR=HI/RS=GI/QS=8/5
9. x/33=18/27
Simplifying the fraction on the right side of the equation:
x/33=2/3
Solving for x: Multiplying both sides of the equation by 33:
33(x/33)=33(2/3)
x=11(2)
x=22
10. x/16=9/12
Simplifying the fraction on the right side of the equation:
x/16=3/4
Solving for x: Multiplying both sides of the equation by 16:
16(x/16)=16(3/4)
x=4(3)
x=12
Answer:
Step-by-step explanation:
59 apples two times = 59 x 2 = 118 apples
Total apples = 118 + 60 = 178 apples
In five weeks, there are 35 days. So, the average drop in temperature per day is 40/35 = 8/7 degrees per week. Then in 1 week, 8/7 degrees per day * 7 days per week = 8 degrees per week.Therefore there are 8 degrees drop of temperature in 1 week.
Problem 1: Plug in the given value into the function and evaluate.

Problem 2: Solve the equation for y.

add 7x to both sides to move it to the right side of the equation.

Divide both sides of the equation by 2 to get a single y variable on the left hand side.

Simplify the terms to get the the equation into slope-intercept form.
The slope of the line is 
I'm a unsure what Problem 3 is asking for sorry I hope the rest is helpful.