Answer:
Mean (Average): 21.44444
Median (Middle): 22
Mode (Most Common): 29
Step-by-step explanation:
First, work out the difference(increase) between the two numbers you are comparing. So, the difference would be <em>100-80</em>, which will equal <em>20</em>.
Then, divide the increase by the original number and multiply the answer by 100. So, that would be <em>20÷100</em>, which would be <em>0.2</em>, then it would be <em>0.2⋅100</em>, so back to <em>20</em>.
The percent of increase should be 20.
Hello :
the line has a equation : y = ax (<span>a y intercept at (0,0))
the slope is : - 1/3 ( product the slope = -1 ..... a×3 = -1)
the equation is : y = (-1/3)x
</span>
P(t) = 40(2)^(kt)
<span>when t=10, (1990), N = 55 </span>
<span>55 = 40(2)^(10k) </span>
<span>1.25 = 2^(10k) </span>
<span>take the ln of both sides, hope you remember your log rules </span>
<span>10k = ln 1.25/ln 2 </span>
<span>10k = .32193 </span>
<span>k = .032193 </span>
<span>so P(t) = 40(2)^(.032193t) </span>
<span>in 2000, t = 20 </span>
<span>P(20) = 40(2)^(.032193(20)) </span>
<span>= 62.5 million </span>
<span>for the formula </span>
<span>P(t) = a(2)^(t/d), d = the doubling time </span>
<span>so changing .032193t to t/d </span>
<span>= .032193t </span>
<span>= t/31.06 </span>
<span>so the doubling time is 31.06 </span>
<span>another way would be to set </span>
<span>80 = 40(2)^(.032193t) </span>
<span>2 = (2)^(.032193t) </span>
<span>.032193t = ln 2/ln 2 = 1 </span>
<span>t = 31.06</span>