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just olya [345]
2 years ago
13

write the equation in point slope form of the line that is perpendicular to 3x-2y=-8 going through the point (-6,5

Mathematics
1 answer:
tatiyna2 years ago
6 0

Answer:

y-5 = -2/3 (x+6)

Step-by-step explanation:

-2y = -3x -8

2y = 3x + 8

2/2 y = 3/2 x + 8/2

y = 3/2 x + 4


slope of a perpendicular line

- 2/3


y-5= -2/3(x-(-6)

y-5 = -2/3 (x+6)

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