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jonny [76]
3 years ago
9

If the diameter of a circle is 9 cm, then its circumference is 56.52 cm. True or false?

Mathematics
1 answer:
Brrunno [24]3 years ago
3 0
Circumference 
2*pi*r
2*(22/7)*(9/2)
2*(11/7)*9
198 / 7
28.28 cm

so 56.52 is not correct
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What is the area of a rectangle with side lengths of 5 12 foot and 2 3 foot
vazorg [7]

Answer:

3 2/3ft²

Step-by-step explanation:

Area of a rectangle = Length × Width

Given

Length = 5 1/2 foot

Width = 2/3foot

Substitute

Area of the rectangle = 5 1/2 × 2/3

Area of the rectangle = 11/2×2/3

Area of the rectangle = 22/6

Area of the rectangle = 11/3

Area of the rectangle = 3 2/3ft²

8 0
3 years ago
The perimeter of a rectangle is 60 centimeters. The base is 2 times the height. What are the dimensions of the rectangle?
tankabanditka [31]
Licenciado en Letrase (base 20 y altura 10 cm. 
3 0
3 years ago
Given m|n, find the value of x and y.
galben [10]

We know that m ║ n.

Let's first find the value 'x'.

When two lines are parallel, and a transversal is drawn, the angles on the same side of the transversal are equivalent.

This means that (5x + 16)° and (7x + 4)° are equivalent.

Equating them,

5x + 16 = 7x + 4

16 - 4 = 7x - 5x

12 = 2x

x = 12/2

x = 6°

Since we know the value of 'x', let's substitute them into the angles and find out the actual measurements.

5x + 16 = 5 × 6 + 16 = 30 + 16 = 46°.

7x + 4 = 7 × 6 + 4 = 42 + 4 = 46°.

Now let's find the value of 'y'.

If you observe carefully, (7x + 4)° and (y + 6)° form a linear pair.

This means that both those angles should add upto 180°.

Using that theory, the following equation can be framed:

(y + 6)°+ (7x + 4)° = 180°

Since we know the actual value of (7x + 4)°, let's substitute that value and move ahead.

(y + 6)° + 46° = 180°

y + 6 + 46° = 180

y + 52° = 180°

y = 180° - 52°

y = 128°

Therefore, the values of 'x' and 'y' are 46° and 128° respectively.

Hope it helps. :)

5 0
3 years ago
Round 3,989.23655 to the nearest thousandth
inysia [295]
3,989.237
A thousandth = 1/1000 = 0.001
Round 4th decimal place = 5
5 and over is rounding up and under 5 rounds down so it would be 3,989.237
6 0
3 years ago
How much taller was Mt. Everest determined to be in 1999, than in 1852? 11 meters 12 meters 22 meters 147 meters
katen-ka-za [31]

Answer:

11 meters

Step-by-step explanation:

In 1852 its height was 29.002ft or 8.839m, while the measuring in 1999 said that it was 29.035ft or 8.850m. That means that it is taller by some 11 meters or 33 feet. That is because it keeps increasing its size since its positioned on such plates that hit each other.

7 0
3 years ago
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