Question

1. Write a function and graph it that has zeros at -2 and 6.2. Make the parabola open up.

Answer 1

we know that

the equation of a vertical parabola is equal to

y=a(x-x1)(x-x2)

where

a is the leading coefficient

x1 and x2 are the zeros of the function

In this problem we have

x1=-2

x2=6

substitute

y=a(x+2)(x-6)

If the parabola open upward, then the coefficient a must be positive

I will assume

a=1

so

y=(x+2)(x-6)

y=x^2-6x+2x-12

y=x^2-4x-12

using a graphing tool