All categories

3 years ago

11) Solve for x: 3(7 + 2x) + 3 = 3(5 + x) − 9(x + 1)

Mathematics

2 answers:

Lerok [7]3 years ago

6 0

Answer:

x = -1.5.

Step-by-step explanation:

3(7 + 2x) + 3 = 3(5 + x) − 9(x + 1)

21 + 6x + 3 = 15 + 3x - 9x - 9

6x - 3x + 9x = 15 - 9 - 21 - 3

12x = -18

x = -18/12

x = -1.5.

gogolik [260]3 years ago

5 0

Step-by-step explanation:

3(7 + 2x) + 3 = 3(5+ x) - 9(x + 1)

21 + 6x + 3 = 15 + 3x - 9x - 9

6x + 24 = 6 - 6x

12x = -18

x = -1.5

You might be interested in

Brainly a geometry teacher asked saul to define "obtuse triangle." saul said that an obtuse triangle is a triangle with one inte

worty [1.4K]

This is true. In order to get an obtuse triangle, one angle must be greater than 90 degrees because the definition of an obtuse triangle is an angle measuring greater than the right angle. The other angles must be less than 90 degrees because the sum of the angles must be 180 degrees.

7 0

4 years ago

Enter the number of complex zeros for the polynomial function in the box.

NikAS [45]

Since the equation has a degree of 5 then, it will definitely have 5 zeroes. Complex zeroes of the polynomial always come in pair such that even if there are five zeroes, the complex zeroes could only be either 2 or 4 or none.

Hence, the answer to this item is none, 2 or 4.

5 0

3 years ago

Read 2 more answers

Help The question is in the picture

marissa [1.9K]

Answer:

Step-by-step explanation:

5 0

3 years ago

The sale price of a table is $472 it was 20% off what was the original price?

ira [324]

To solve, set an equation:

472=0.8x

Divide both sides by 0.8

472/0.8=0.8x/0.8

x=590

Answer: The original price was $590

5 0

3 years ago

Test the null hypothesis Upper H 0 : (mu 1 minus mu 2 )equals 0H0: μ1−μ2=0 versus the alternative hypothesis Upper H Subscript a

Law Incorporation [45]

Answer:

The test statistic t is t=2.9037.

The null hypothesis is rejected.

For a significance level of 0.05, there is enough evidence to support the alternative hypothesis.

Step-by-step explanation:

The question is incomplete:

The sample 1, of size n1=25 has a mean of 1.15 and a standard deviation of 0.31.

The sample 2, of size n2=25 has a mean of 0.95 and a standard deviation of 0.15.

This is a hypothesis test for the difference between populations means.

The null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2\neq 0$

The significance level is α=0.05.

The difference between sample means is Md=0.2.

$M_d=M_1-M_2=1.15-0.95=0.2$

The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2+\sigma_2^2}{n}}=\sqrt{\dfrac{0.31^2+0.15^2}{25}}\\\\\\s_{M_d}=\sqrt{\dfrac{0.119}{25}}=\sqrt{0.005}=0.069$

Then, we can calculate the t-statistic as:

$t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{0.2-0}{0.069}=\dfrac{0.2}{0.069}=2.9037$

The degrees of freedom for this test are:

$df=n_1+n_2-1=25+25-2=48$

This test is a two-tailed test, with 48 degrees of freedom and t=2.9037, so the P-value for this test is calculated as (using a t-table):

$P-value=2\cdot P(t>2.9037)=0.0056$

As the P-value (0.0056) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

8 0

4 years ago