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eimsori [14]
11 months ago
14

How can I solve 4x^2 + 12x > -x -3

Mathematics
1 answer:
Damm [24]11 months ago
5 0

He have the following:

4x^2+12x>-x-3​

solving:

\begin{gathered} 4x^2+12x+x+3>-x-3+x+3​ \\ 4x^2+13x+3>0 \\ \text{factoring} \\ (4x+1)(x+3)>0 \\ (4x+1)>0\rightarrow4x+1-1>-1\rightarrow\frac{4x}{4}>-\frac{1}{4}\rightarrow x>-\frac{1}{4} \\ (x+3)

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What is the sum of 2/5 and 2/4
Helga [31]
9/10....................................
5 0
2 years ago
X-1/x-2+x+3/x-4=2/(x-2).(4-x)
Varvara68 [4.7K]

The given equation x-1/x-2+x+3/x-4=2/(x-2).(4-x) is correct. the answer is proved.

According to the statement

we have given that the equation and we have to prove that the given answer is a correct answer for those equivalent equation.

So, The given expression are:

\frac{x-1}{x-2} +\frac{x+3}{x-4} = \frac{2}{(x-2).(4-x)}

And we have to prove the answer.

So, For this

\frac{x-1}{x-2} +\frac{x+3}{x-4}

\frac{({x-1}) ({x-4}) +({x+3})({x-2})} {(x-2) (x-4)}

Then the equation become

\frac{x^{2} -4x -x +4 + x^{2} -2x + 3x -6 }{(x-2) (x-4)}

Now solve it then

2x^{2} - 4x -2 / (x-2) (x-4)

Now take 2 common from answer then equation become

\frac{x-1}{x-2} +\frac{x+3}{x-4} = \frac{2}{(x-2).(4-x)}

Hence proved.

So, The given equation x-1/x-2+x+3/x-4=2/(x-2).(4-x) is correct. the answer is proved.

Learn more about equations here

brainly.com/question/2972832

#SPJ1

3 0
1 year ago
!! please help !!!!!!!!!!!!!!
Ludmilka [50]

Answer:

1=angle CAS

2=point T

3=

8 0
3 years ago
Read 2 more answers
Find the area of the shaded region. (You may express your answer in<br><br>terms of π.)
erastova [34]

Answer:

a. 16π cm²

b. 24π cm²

c. 33 1/3π cm²

d. 64π-128 cm²

e. 144π-288 cm²

Step-by-step explanation:

To find area of shaded region, find area of whole circle then divide the area where you're left with the area of the shaded region. For the problems with the triangles you find the area of the triangle then subtract that from a fourth of the area of the circle.

Area of a circle = πr²

a.

r=8cm

Area of circle=64π cm²

Shaded region=16π cm²

b.

r=12cm

Area of circle=144π cm²

Shaded region=24π cm²

c.

r=10cm

Area of circle=100π cm²

Shaded region=33 1/3π cm²

d.

r=16cm

Area of circle=256π cm²

Area of triangle=128 cm²

Shaded region=64π-128 cm²

e.

r=24

Area of circle=576π cm²

Area of triangle=288 cm²

Shaded region=144π-288 cm²

4 0
2 years ago
Is the answer to 6 divided by 2/3=N 1
xeze [42]
No the answer would be 9.

6 * 3/2 (switch it up now and do 6 * 3/2)

18/2 (simplify)

9 (simplify)
8 0
3 years ago
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