Answer:
Step-by-step explanation:
Given that every day at noon, a bus leaves for Townville and travels at a speed of x kilometers per hour. Today, the bus left 30 minutes late.
If the driver drives 7/6 times as fast as usual, she will arrive in Townville at the regular time.
If correct time leaves then distance = time *speed
280 = t*x where t is the time in hours
Or t = 280/x
Now speed changes to 7x/6 while time changes to (t-1/2)
So 280 = (t-1/2) 7x/6
![280 = (\frac{280}{x} -\frac{1}{2} )(\frac{7x}{6} )\\240= (\frac{280}{x} -\frac{1}{2} )x\\\\x=80](https://tex.z-dn.net/?f=280%20%3D%20%28%5Cfrac%7B280%7D%7Bx%7D%20-%5Cfrac%7B1%7D%7B2%7D%20%29%28%5Cfrac%7B7x%7D%7B6%7D%20%29%5C%5C240%3D%20%20%28%5Cfrac%7B280%7D%7Bx%7D%20-%5Cfrac%7B1%7D%7B2%7D%20%29x%5C%5C%5C%5Cx%3D80)
x = 80 km per hour
The expression would equal 6
If markup is 60% of the cost, you have
... markup = 0.60×cost
... markup/0.60 = cost
... $207.20/0.60 = cost = $345.33
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If markup is 60% of the selling price, the other 40% is the cost. So, the cost is 40/60 = 2/3 of the markup.
... cost = (2/3)×markup = (2/3)×$207.20
... cost = $138.13
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Markup can be specified in terms of either selling price or cost. Those are the usual reference values; there could be others. When only the percentage is given, you don't have enough information to work the problem. You need to know what it is a percentage of. (Example problems in your text may tell you the expected interpretation.)
Answer:
With the formula of lwh/3 the answer is 305.37
Step-by-step explanation:
l×w×h /3 =305.37