Answer:
diameter = m - c
Step-by-step explanation:
In ΔABC, let ∠C be the right angle. The length of the tangents from point C to the inscribed circle are "r", the radius. Then the lengths of tangents from point A are (b-r), and those from point B have length (a-r).
The sum of the lengths of the tangents from points A and B on side "c" is ...
(b-r) +(a-r) = c
(a+b) -2r = c
Now, the problem statement defines the sum of side lengths as ...
a+b = m
and, of course, the diameter (d) is 2r, so we can rewrite the above equation as ...
m -d = c
m - c = d . . . . add d-c
The diameter of the inscribed circle is the difference between the sum of leg lengths and the hypotenuse.
Given:
m∠NRQ = 60°
To find:
The angle measure of minor arc NQ
Solution:
The inscribed angle is half of the intercepted arc.
Multiply by 2 on both sides.
Substitute m∠NRQ = 60°.
The measure of minor arc NQ is 120°.
Given:
22
gallons of 16% ammonia
24%
ammonia
Find:
Number
of gallons of water to remove
Solution:
Let
n = number of gallons needed to obtain 24% ammonia
22
gallons (0.16) = n (.24)
<span>N = 14.67 gallons of water</span>
