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Nitella [24]
2 years ago
7

Write an equation in slope - intercept form for the line that passes through the given paint andis perpendicular to the given éq

uation.9.(-3, -2), y = -2x+ 4
Mathematics
1 answer:
lutik1710 [3]2 years ago
7 0

Given the equation y=-2x+4, we can easily find the slope of the perpendicular line by calculating the inverse negative of the slope. This is:

\begin{gathered} y=-2x+4 \\ m=-2 \\ m_p=-\frac{1}{m} \\ \Rightarrow m_p=-\frac{1}{-2}=\frac{1}{2} \\ m_p=\frac{1}{2} \end{gathered}

Now that we have the slope, we can ouse the equation slope-intercept to find the intercept b using the point (-3,-2):

\begin{gathered} m_p=\frac{1}{2} \\ (x,y)=(-3,-2) \\ y=mx+b \\ \Rightarrow-2=\frac{1}{2}(-3)+b \\ \Rightarrow-2+\frac{3}{2}=b \\ \Rightarrow b=-\frac{1}{2} \end{gathered}

Therefore, the equation in slope-intercept form is:

y=\frac{1}{2}x-\frac{1}{2}

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Answer:

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Step-by-step explanation:

Let the random variable <em>X</em> denote the weight of the parts.

The random variable <em>X</em> is normally distributed with parameters, <em>μ</em> = 1 lb and <em>σ</em> = 0.20 lb.

It is provided that a shipping pallet holds 10 boxes and each box holds 300 parts of different types.

That is, there are a total of 300 × 10 = 3000 parts in a pallet.

(a)

Compute the mean and standard deviation of the pallet weight as follows:

Mean of the pallet weight = n × E (X)

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Standard deviation of the pallet weight = \sqrt{3000\times V(X)}

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Thus, the mean and standard deviation of the pallet weight are 3000 lb and 10.95 lb respectively.

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Compute the probability that the pallet weight (W) will exceed 3015 lb as follows:

P(W>3015)=P(\frac{W-\mu}{\sigma}>\frac{3015-3000}{10.95})

                     =P(Z>1.37)\\\\=1-P(Z

*Use a <em>z</em>-table.

Thus, the probability that the pallet weight (W) will exceed 3015 lb is 0.085.

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