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1 year ago

What does it mean by a 11th grader or does not have a smart phone I need explanationAnswer Question 4c

Mathematics

1 answer:

IRISSAK [1]1 year ago

7 0

Answer:

Explanation:

Given:

To find:

The probability that a student is an 11th grader or does not have a smartphone

From the table, we can see that;

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3 years ago

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3 years ago

Sue has 18 sweets.

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3 years ago

Read 2 more answers

Solve the equation log^7b>2

ahrayia [7]

Answer:

b > 12.71

Step-by-step explanation:

Here in this question we have to solve the inequality equation given for b (An unknown variable}

Now, the equation is $(\log b)^{7} > 2$

⇒ $\log b > 2^{\frac{1}{7} }$

We are taking the base of the log here is 10.

So, $10^{(\log b)} > 10^{2^{\frac{1}{7} } }$ {Since $10^{\log x} =x$ and $e^{\ln x} = x$ }

⇒ b > 12.71 (Approximate) (Answer)

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3 years ago

What is the difference in area covered by a single 3 inch windshield wiper operating with a central angle of 138 degrees compare

Elena-2011 [213]

Answer:

38.9 square inches.

Step-by-step explanation:

We are asked to find the difference in area covered by a single 3 inch windshield wiper operating with a central angle of 138 degrees compared to a pair of 5 inch wipers operating together each having a central angle of 114 degrees.

We will use area of sector formula to solve our given problem as:

$\text{Area of sector}=\frac{\theta}{360}\times \pi r^2$ , where, r represents radius and theta represents central angle.

Let us find area of sector with central angle 140 degree and radius 3 inch.

$\text{Area of sector}=\frac{138}{360}\times \pi (3)^2$

$\text{Area of sector}=\frac{138}{360}\times 9\pi$

$\text{Area of sector}=10.83849$

Now, we will find area of sector with central angle 114 degree and radius 5 inch and multiply by 2 as:

$\text{Area of sector}=2(\frac{114}{360}\times \pi (5)^2)$

$\text{Area of sector}=2(\frac{114}{360}\times 25\pi)$

$\text{Area of sector}=\frac{114}{360}\times 50\pi$

$\text{Area of sector}=49.74188$

Let us find difference of area as shown below:

$\text{Difference of areas}=49.74188-10.83849$

$\text{Difference of areas}=38.90339$

$\text{Difference of areas}\approx 38.9$

Therefore, the difference in area covered is approximately 38.9 square inches.

8 0

3 years ago