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geniusboy [140]
3 years ago
14

my ones digit is 0. my tens digit is 7 more than my ones digit. my hundreds digit is 6 more than my ones digit. i am the number​

Mathematics
2 answers:
Likurg_2 [28]3 years ago
4 0

The tens digit is 7 more than the ones digits, so it's 7 more than 0, so it's 7.

Similarly, the hundreds digit is 6.

So, the number is 670

OleMash [197]3 years ago
3 0
The answer is the number 670
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Answer questions below<br> ASAP<br> 5-1/2x=5/8x+2
jeka57 [31]
Answer:   x = 8/3 ; or, write as:  2 2/3; or, write as, 2.66666667 .
_________________________________________________________
Explanation:
_________________________________________________________

 Given:   5 − 1/2 x = 5/8 x + 2 ;
______________________________________________________
    Change the  1/2 x  to "4/8 x" ;
_________________________________________________
Since "1/2" = "(1*4)/(2*4)" = "(4/8)"; and rewrite:
_________________________________________________
      → 5 − (4/8)x = (5/8)x + 2 ;
_________________________________________________
  Subtract "5"; and add "(5/8)x" to EACH side of the equation:
________________________________________________
 5 − (4/8)x  −  5 + (5/8)x  =  (5/8)x  + 2 − 5 + (5/8)x ;
_________________________________________________
to get:
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                 (1/8) x = (10/8)x  − 3
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Multiply the entire equation (BOTH SIDES) by "8"; to get rid of the fraction:
_________________________________________________________

8 * { (1/8) x = (10/8)x − 3 }; 
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     to get:
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              x = 10x − 24 ;
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Subtract "x" ; and add "24" ; to EACH side of the equation:
____________________________________________________
       →      x − x + 24 =  10x − 24  − x  + 24 ;
____________________________________________________
       to get:
_____________________________________________________
            →  24  = 9x ; ↔  9x = 24 ;
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  → Divide EACH side of the equation by "9" ; to isolate "x" on one side of the equation; and to solve for "x" ;
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        → 9x / 9 = 24 / 9 ;
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        →    x = 24/9 = (24÷3)/ (9÷3) = 8/3
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        →    x = 8/3 ; or, write as:  2 2/3; or, write as, 2.66666667.
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5 0
4 years ago
Give an example of a function F(x) that is an antiderivative of f(x) = 9 cos(9x)+ 3x^2
liubo4ka [24]

We are integrating f(x) = 9cos(9x) + 3x²:    \int\ {9cos(9x)+3x^{2} } \, dx

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b) Calculate each antiderivative

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\int\ {9cos(9x)} \, dx

1. Take out the constant

9\int\ {cos(9x)} \, dx

2. Apply u-substitution, where u is 9x

9\int\ {cos(u)\frac{1}{9} }  du

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4. Take the common integral of cos, which is sin

9*\frac{1}{9}sin(u)}

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6. Always remember to add an arbitrary constant, C, at the end

sin(9x) + C

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\int3x^{2} } \, dx

1. Take out the constant

3\int{x^{2} } \, dx

2. Apply the power rule, \int{x}^{a}  \, dx =\frac{x^{a+1} }{a+1}, where <em>a</em> is your exponent

⇒ 3*\frac{x^{2+1} }{2+1}  = x^{3}

3. Add the arbitrary constant

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Notice the two arbitrary constants.  Since we do not know what either constant is, we can combine them into one arbitrary constant.

<h3>Answer:</h3>

F(x) = sin(9x) + x³ + C

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Andrew [12]

Answer:

(-3, 4)

General Formulas and Concepts:

<u>Pre-Algebra</u>

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<u>Algebra I</u>

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Step-by-step explanation:

<u>Step 1: Define Systems</u>

y = -x + 1

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<u>Step 2: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

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hammer [34]
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