$\dfrac{2x-3}{x}:\dfrac{7}{x^2}=\dfrac{2x-3}{x}\cdot\dfrac{x^2}{7}=\dfrac{2x-3}{1}\cdot\dfrac{x}{7}\\\\=\dfrac{(2x-3)\cdot x}{1\cdot7}=\dfrac{2x^2-3x}{7}$

4 0

3 years ago

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Can I get him with all the questions please?

lara [203]

Answer:

$14.16\\15. a) 14$

Step-by-step explanation:

$14. We\ are\ given\ that,\\The\ assumed\ number\ x\ is\ 4\ more\ than\ 12\\Hence,\\x=4+12\\x=16\\Lets\ see\ that\ x=16\ as\ a\ solution,\ matches\ with\ the\ other\ information\ provided.\\We\ are\ also\ given\ that,\\x13, 16\ is\ greater\ than\ 13\ too.\\x$

$15. a)\\Let\ the\ assumed\ no.\ be\ y\\Here,\ we\ are\ given\ the\ following\ information\ about\ y:\\y>10,\\y12\\y13,\\y=14$

5 0

3 years ago

What is 58,000,000 in scientific notation

AleksAgata [21]

5.8*(7^10)
Hope this help

5 0

3 years ago

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