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allochka39001 [22]
3 years ago
11

kevin borrowed $32,500 to purchase a new car. If the rate on the loan is 6% compounded annually, how much will he pay in total o

ver the course of the 5 year loan?
Mathematics
1 answer:
VLD [36.1K]3 years ago
3 0

Answer: He would pay $43492.33 in total over the course of the 5 years.

Step-by-step explanation:

Since we have given that

Amount he borrowed = $32500

Rate of compounded annually = 6%

Number of years = 5 yr

As we know the formula for "Compound Interest':

A=P(1+\frac{r}{100})^n\\\\A=32500(1+\frac{6}{100})^5\\\\A=32500(\frac{100+6}{100})^5\\\\A=32500(1.06)^5\\\\A=\$43492.33

Hence, He would pay $43492.33 in total over the course of the 5 years.

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Which equation shows the relationship between the volume, (V) of the prism and its height (h)?
denis-greek [22]

Answer:

h = V/lw

Step-by-step explanation:

We know the formula for the volume of a rectangular prism is V = lwh. We need to use this equation and solve for h by dividing lw on both sides.

V = lwh

V/lw = h

4 0
3 years ago
the point P = (x, 1/2) lies on the unit curcle shown below. what is the value of x in the simplest form
Mrac [35]

Answer:

x=sqrt(3)/2 or -sqrt(3)/2

Step-by-step explanation:

(x,1/2) is on the unit circle at pi/6 and 5pi/6.

so x is either sqrt(3)/2 or -sqrt(3)/2

5 0
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Which pair of equations represents two perpendicular lines? <br>answers shown in picture. ​
kolezko [41]

Answer:

y =1/2x+6

y = -2x+2

Step-by-step explanation:

Perpendicular line have slopes that multiply to -1

The slopes are negative reciprocals

-4*4 = 16  not perpendicular

1/2 * -2 = -1  perpendicular

1/5 *5 = 1  not perpendicular

2/3 * 2/3 = 4/9  not perpendicular

3 0
3 years ago
What is the coefficient of the x5y5-term in the binomial expansion of (2x – 3y)10? 10C5(2)5(3)5 10C5(2)5(–3)5 –10C5(2)5(–3)5 10C
butalik [34]

ANSWER

10C_5(2)^{5}( - 3)^5

EXPLANATION

The given binomial expansion is:

{(2x - 3y)}^{10}

Compare this to

{(a + b)}^{n}

we have a=2x , b=-3y and n=10

We want to find the coefficient of the term

{x}^{5}  {y}^{5}

This implies that, r=5.

The terms in the expansion can be obtained using

T_{r+1}=nC_ra^{n-r}b^r

We substitute the given values to obtain;

T_{5+1}=10C_5(2x)^{10-5}(  - 3y)^5

T_{6}=10C_5(2x)^{5}(3y)^5

T_{6}=10C_5(2)^{5}( - 3)^5 {x}^{5}  {y}^{5}

Hence the coefficient is;

10C_5(2)^{5}( - 3)^5

5 0
3 years ago
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today, 6 friends went out for lunch. their total Bill was $41.88, including tax and gratuity. they decide to split the Bill equa
Mariulka [41]
Each person will get back $3.02

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3 years ago
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