Question

The formula for the volume of a cone is V = jarh, where V is the volume, r is the radius, and h Is the heightWhat is the volume of a cone with a radius of 4x and a height of 21xy^2??

Answer 1

Given:

The radius, r=4x

The height,

$h=21xy^2$

To find the volume of the cone:

The volume of the cone formula is,

$V=\frac{1}{3}\pi r^2h$

Substitute the values of r and h in the above formula we get,

$\begin{gathered} V=\frac{1}{3}\pi\times(4x)^2\times21xy^2 \\ =\frac{1}{3}\pi\times16x^2\times21xy^2 \\ =\pi\times16x^2\times7xy^2 \\ =112\pi x^3y^2 \end{gathered}$

Hence, the volume of the cone is

$V=112\pi x^3y^2$

Thus, the correct option is option D.