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2 years ago

Michelle cut 1/4 yard of ribbon into 4 equal pieces what is the length of each equal piece

Mathematics

1 answer:

aleksandr82 [10.1K]2 years ago

7 0

I think the answer is 16 because 1\4 divided by 4 equals 1/16 or 16

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Yakvenalex [24]

Step-by-step explanation:

Subtract initial amount (300) and final (150). from there you get 150 dollars that was lost. We know that every step you 5 dollars so then divide 150 and 5 to get 30. So the distance was 30 steps.

3 0

3 years ago

Hope someone help.me

zvonat [6]

x = r sin θ cos Ф

x² = r² sin² θ cos² Ф

y = r sin θ sin Ф

y² = r² sin² θ sin² Ф

z = r cos θ

z² = r² cos² θ

x² + y² + z²

= r² sin² θ cos² Ф + r² sin² θ sin² Ф + r² cos² θ

= r² sin² θ (cos² Ф + sin² Ф) + r² cos² θ

= r² sin² θ + r² cos² θ

= r² (sin² θ + cos² θ)

= r² √

7 0

3 years ago

What is the difference of the fractions? Use the number line to help find the answer.

noname [10]

The result of the expressionn 1/5 - 3/4 will be negative 11/20. Then the correct option is C.

<h3>What is a fraction number?</h3>

A fraction number is a number that represents the part of the whole, where the whole can be any number. It is in the form of numerator and denominator.

The expression is given below.

⇒ 1/5 - 3/4

⇒ (4 - 15) / 20

⇒ -11 / 20

Then the correct option is C.

More about the fraction number link is given below.

brainly.com/question/78672

#SPJ1

5 0

2 years ago

The coordinate notation for a translation 5 units right and 6 units down is?

wariber [46]

(x+5,y-6) is the coordinate notation.

4 0

2 years ago

Chose parameters h and k such that the system has a) a unique solution, b) many solutions, and c) no solution. X1 + 3x2 = 4 2x1

AysviL [449]

Answer:

a) The system has a unique solution for $k\neq 6$ and any value of $h$ , and we say the system is consisted

b) The system has infinite solutions for $k=6$ and $h=8$

c) The system has no solution for $k=6$ and $h\neq 8$

Step-by-step explanation:

Since we need to base the solutions of the system on one of the independent terms ( $h$ ), the determinant method is not suitable and therefore we use the Gauss elimination method.

The first step is to write our system in the augmented matrix form:

$\left[\begin{array}{cc|c}1&3&4\\2&k&h\end{array}\right]$

The we can use the transformation $r_0\rightarrow r_0 -2r_1$ , obtaining:

$\left[\begin{array}{cc|c}1&3&4\\0&k-6&h-8\end{array}\right]$ .

Now we can start the analysis:

If $k\neq 6$ then, the system has a unique solution for any value of $k$ , meaning that the last row will transform back to the equation as:

$(k-6)x_2=h-8\\x_2=h-8/(k-6)$

from where we can see that only in the case of $k=6$ the value of $x_2$ can not be determined.

if $k=6$ and $h=8$ the system has infinite solutions: this is very simple to see by substituting these values in the equation resulting from the last row:

$(k-6)x_2=h-8\\0=0$ which means that the second equation is a linear combination of the first one. Therefore, we can solve the first equation to get $x_1$ as a function of $x_2$ o viceversa. Thus, $x_2$ ( $x_1$ ) is called a parameter since there are no constraints on what values they can take on.

if $k=6$ and $h\neq 8$ the system has no solution. Again by substituting in the equation resulting from the last row:

$(k-6)x_2=h-8\\0=h-8$ which is false for all values of $h\neq 8$ and since we have something that is not possible $(0\neq h-8,\ \forall \ h\neq 8)$ the system has no solution

6 0

3 years ago