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kherson [118]
1 year ago
8

You are dealt one card from a standard 52-card deck. Find the probability of being dealt the queen of diamonds.

Mathematics
1 answer:
Daniel [21]1 year ago
4 0

We need to find the probability of being dealt the queen of diamonds when you are dealt one card from a standard 52-card deck.

A standard deck has four queens. And just one of them is a queen of diamonds.

Thus, 1 out of 52 cards is the queen of diamonds.

Therefore, the probability of being dealt the queen of diamonds is given by 1 divided by 52:

\frac{1}{52}

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the perimeter of the rectangle below is 98 units. Find the length of CD. Write your answer without variables. cd=4x+3 cb=5x+1
zimovet [89]

2(4x + 3) + 2(5x + 1) = 98 \\ 8x + 6 + 10x + 2 = 98 \\ 18x + 8 = 98 \\ 18x = 90 \\  x = 5
Substitute x with 5,

CD =
4x + 3 \\  = 4(5) + 3 \\  = 20 + 3 \\  = 23
CD = 23 units

Hope this helps.
7 0
3 years ago
Read 2 more answers
What is the answer to 16> 1.5 + 0.8b
user100 [1]

Answer:

16>2.3b

Step-by-step explanation:

1.5+0.8=2.3

Substitute b as 1. Which would still keep it as 2.3.

8 0
3 years ago
Derive the equation of the parabola with a focus at (6,2) and a directrix of y=1
nydimaria [60]
Distance from focus to vertex=distance from vertex to directix

from (6,2) to y=1, the distance is 1
the focus is 1/2 higher than the vertex
vertex=(6,1.5)

for
(x-h)^2=4p(y-k)
vertex=(h,k)
p=distance from vertex to directix

vertex=(6,1.5)
ditance=0.5

(x-6)^2=4(0.5)(y-1.5)
(x-6)^2=2(y-1.5) is the equation
or
y=0.5x^2-6x+19.5 or
y=0.5(x-6)^2+1.5
7 0
3 years ago
Read 2 more answers
F(x) = x + 4 and g(x) = 2x + 3, evaluate each expression.
Rom4ik [11]

Answer:

15.~f(g(2))=\Large\boxed{11}\\

16.~g(f(2.5))=\Large\boxed{16}

17.~g(f(-5))=\Large\boxed{1}

18.~f(g(-5))=\Large\boxed{-3}

Step-by-step explanation:

<h3>Given information</h3>

f(x)=x+4

g(x)=2x+3

<h3>Question 15. f(g(2))</h3>

<u>Substitute values into the first function</u>

g(2)=2(2)+3

g(2)=4+3

g(2)=7

<u>Substitute the values of the first function into the second</u>

f(g(2))=f(7)

f(7)=(7)+4

f(7)=\Large\boxed{11}

<h3>Question 16. g(f(2.5))</h3>

<u>Substitute values into the first function</u>

f(2.5)=(2.5)+4

f(2.5)=6.5

<u />

<u>Substitute the values of the first function into the second</u>

g(f(2.5))=g(6.5)

g(6.5)=2(6.5)+3

g(6.5)=13+3

g(6.5)=\Large\boxed{16}

<h3>Question 17. g(f(-5))</h3>

<u>Substitute values into the first function</u>

f(-5)=(-5)+4

f(-5)=-1

<u>Substitute the values of the first function into the second</u>

g(f(-5))=g(-1)

g(-1)=2(-1)+3

g(-1)=-2+3

g(-1)=\Large\boxed{1}

<h3>Question 18. f(g(-5))</h3>

<u>Substitute values into the first function</u>

g(-5)=2(-5)+3

g(-5)=-10+3

g(-5)=-7

<u>Substitute the values of the first function into the second</u>

f(g(-5))=f(-7)

f(-7)=(-7)+4

f(-7)=\Large\boxed{-3}

Hope this helps!! :)

Please let me know if you have any questions

7 0
2 years ago
32 customers in 4 checkout lanes
viva [34]
I don’t know what the question is but it would be 8 divides out evenly
5 0
3 years ago
Read 2 more answers
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