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ANEK [815]
3 years ago
5

I need help on math please

Mathematics
2 answers:
Afina-wow [57]3 years ago
8 0
3.
a. y=28.4x
b. 4,260 grams in 150 ounces

4. 2b - 11
Vitek1552 [10]3 years ago
6 0

Answer:

y=28.4x

Step-by-step explanation:

sorry I couldnt do the rest I'm in a rush

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Find how many quarts of 6?% butterfat milk and 3?% butterfat milk should be mixed to yield 30 quarts of 5?% butterfat milk
Mrrafil [7]

Answer:

The 20  quarts are used for 6% butterfat milk and 10 quarts are used for  3% butterfat milk .

Step-by-step explanation:

As given

6% butterfat milk and 3% butterfat milk should be mixed to yield 30 quarts of 5% butterfat milk .

Let us assume that x quarts are used for 6% butterfat milk .

Than (30 - x) quarts are used for 3% butterfat milk .

6% is written in the decimal form

= \frac{6}{100}

= 0.06

3% is written in the decimal form

= \frac{3}{100}

= 0.03

5% is written in the decimal form

= \frac{5}{100}

= 0.05

Than the equation becomes

0.06 × x + (30 - x) × 0.03 = 30 × 0.05

0.06x + 0.9 - 0.03x = 1.5

0.06x  - 0.03x = 1.5 - 0.9

0.03x  = 0.6

x = \frac{0.6}{0.03}

x = 20 quarts for 6% butterfat milk  .

(30 - x ) = (30 - 20) = 10 quarts for 3% butterfat milk  .

Than 20  quarts are used for 6% butterfat milk and 10 quarts are used for  3% butterfat milk .




5 0
4 years ago
<img src="https://tex.z-dn.net/?f=2%20%5Ctimes%202" id="TexFormula1" title="2 \times 2" alt="2 \times 2" align="absmiddle" class
EastWind [94]
4 (i literally had to think about this cause i thought it was too easy )
6 0
3 years ago
Calculate the mean deviation by median (by using the mid-point(x) of leaf weights. b) A fair die is rolled. Find the probability
SVETLANKA909090 [29]

Answer:

hello attached below is the required table that is missing and the completed table as well

A) mean deviation = 0.1645

B) 2/3

Step-by-step explanation:

From the table we calculated the midpoint value (x) and c.f

N = 27

median class = 2.35 to 2.45

median = l + [ (N/2) - cf / F ] * H

             = 2.35  + [ (13.5 - 13) / 6 ] *0.1 = 2.3583

hence mean deviation by median

= summation of  fi |xi -M| / summation of fi

= 4.4417 / 27 = 0.1645

B ) probability of getting an odd number or prime number or both

the probability of an odd number = 1/2

also the probability of an even number = 1/2

while the probability of getting neither of them = 1/3

hence the probability of getting odd or prime or both

= 1/2 + 1/2 - 1/3 = 2/3

6 0
3 years ago
What is the median of this set of data?
Vladimir [108]

Answer:

The median would be 103.

8 0
3 years ago
Read 2 more answers
Find the slope of the given points (3.4) and (7,4)
cluponka [151]

Answer:

y=0x+4

Step-by-step explanation:

7 0
3 years ago
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