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horsena [70]
1 year ago
13

3. A dining hall had a total of 18 tables - some long rectangular tables and some round ones. Long tables canseat 8 people. Roun

d tables can seat 6 people. On a busy evening, all 130 seats at the tables are occupied.Write a system of equations that can be used to determine how many rectangular tables and round tables arebeing used that evening.
Mathematics
1 answer:
ziro4ka [17]1 year ago
6 0

We define the following variables:

R = # of rectamgular tables

C = # of circular tables

From the statement we know that we have a total of 18 tables, so the # of rect. tables plus the # of circ. tables must sum 18:

18=R+C

We also know that we have 130 occupied seats, so we can write the following equation in terms of R and C (taking in account that each one can have 8 and 6 persons, respectively):

130=8\cdot R+6\cdot C

So we must solve the following system of equations:

\begin{gathered} 18=R+C \\ 130=8R+6C \end{gathered}

In order to solve the system we can do the following steps:

undefined

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A–2=3+6a/3 what is the value of a
beks73 [17]
I am thinking A is -5
7 0
4 years ago
What proportion results in the equation 9m= 100?
lubasha [3.4K]

Answer:

c

Step-by-step explanation:

hope this helps you out

3 0
4 years ago
2) 3x + 4y = 8<br> 2x+y=42<br> a) (30, -19)<br> b) (31, -20)<br> c) (32,-22)<br> What is the answer
kirza4 [7]

Answer:

C

Step-by-step explanation:

We can solve simultaneous equations using substitution method, elimination method or graphical method. But for this purpose, we will be using the elimination method.

3x+4y=8 Equation 1

2x+y=42 Equation 2

Multiply Equation 1 by 2 and equation 2 by 3, so as to get the same coefficient for x

2(3x+4y=8)= 6x+8y=16 Equation 3

3(2x+y=42)= 6x+3y=126 Equation 4

Subtract equation 4 from 3, to eliminate x

6x-6x=0

8y-3y= 5y

16-126= -110

We now have 5y=-110

Divide both sides by 5,

y= -110/5

= -22

Substituting for y in equation 2

2x+(-22)= 42

2x= 42+22

2x=64

x= 64/2

= 32

(x, y)

(32, -22)

7 0
3 years ago
Calculate the total surface area of a pipe with inner surface area 1508.5 square cm, outer surface area 2514.2 square cm, and in
algol [13]

Answer:

The total surface area of the pipe is 4123.31 cm²

Step-by-step explanation:

Total surface area (TSA) of a pipe is calculated as;

Outer area of the pipe + Inner area of the pipe + cross section of the two ends

TSA = 2πRL + 2πrL + 2π(R² - r²)

TSA = 2π(RL + rL + R² - r²)

where;

R is the outer radius

r is the inner radius

L is length of the pipe

Determine the length of the pipe

Outer surface area of the pipe is  calculated as;

outer surface of the pipe = 2πRL

2514.2  = 2πRL

2514.2 = (2π x 5) L

2514.2 = 31.42 L

L = 2514.2 / 31.42

L = 80.02 cm

Finally, determine the total surface area of the pipe

TSA = 2π(RL + rL + R² - r²)

TSA = 2π(5x80.02 + 3x80.02 + 5² - 3²)

TSA =  2π(400.1 + 240.06 + 16)

TSA =  2π(656.16)

TSA = 4123.31 cm²

Therefore, the total surface area of the pipe is 4123.31 cm²

8 0
4 years ago
Using suitable property solve<br> -3/4*2/3+3/4*-5/6
REY [17]

Answer: The answer is -1/8

Step-by-step explanation:

3/4*2/3+3/4*-5/6

3 is cancelled out with 3, 4 with 2, 3 with 6

1/2-5/8

take the L.C.M

4(1)-1(5)/8

4-5/8

=-1/8

3 0
3 years ago
Read 2 more answers
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