Question

What is the center of a circle whose equation is x2 y2 4x – 8y 11 = 0?

Answer 1

The equation of the circle x² + y² + 4x – 8y + 11 = 0 that has radius of 3 units and center at (–2, 4).

What is a circle?

It is a locus of a point drawn equidistant from the center. The distance from the center to the circumference is called the radius of the circle.

The equation of the circle is x² + y² + 4x – 8y + 11 = 0

Add 9 on both sides of the equation, then we have

x² + y² + 4x – 8y + 11 + 9 = 9

x² + 4x + 4 + y² – 8y + 16 = 9

             (x + 2)² + (y – 4)² = 3²

The center of the equation is (–2, 4).

More about the circle link is given below.

brainly.com/question/11833983