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Elden [556K]
2 years ago
15

What is the center of a circle whose equation is x2 y2 4x – 8y 11 = 0?

Mathematics
1 answer:
sergejj [24]2 years ago
7 0

The equation of the circle x² + y² + 4x – 8y + 11 = 0 that has radius of 3 units and center at (–2, 4).

<h3>What is a circle?</h3>

It is a locus of a point drawn equidistant from the center. The distance from the center to the circumference is called the radius of the circle.

The equation of the circle is x² + y² + 4x – 8y + 11 = 0

Add 9 on both sides of the equation, then we have

x² + y² + 4x – 8y + 11 + 9 = 9

x² + 4x + 4 + y² – 8y + 16 = 9

             (x + 2)² + (y – 4)² = 3²

The center of the equation is (–2, 4).

More about the circle link is given below.

brainly.com/question/11833983

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Answer:

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3 years ago
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A rectangular cracker has a length of 5 centimeters and an area f 20 square centimeters. Find its perimeter.
iren [92.7K]

Answer:

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Step-by-step explanation:

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a = l * w

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The rectangle is going to have two sides that are the length of l, and two sides that are the the length of w. We're looking for the perimiter p.

p = 2l + 2w

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2 years ago
What are the exact solutions of x2 - 3x - 5 = 0? x = the quantity of negative 3 plus or minus the square root of 29 all over 2 x
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<em>\\\ Ben</em>
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3 years ago
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