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1 year ago

Please help with this question

Mathematics

1 answer:

Slav-nsk [51]1 year ago

7 0

Answer:

A is correct. √11 and √14 are both between 3 and 4.

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A Florida poll asked 1200 Floridians whether they would prefer an increase in taxes or a decrease in government services as a wa

mojhsa [17]

Answer:

Step-by-step explanation:

Given that a lorida poll asked 1200 Floridians whether they would prefer an increase in taxes or a decrease in government services as a way to balance the budget.

$H_0: p =0.50\\H_a: p >0.50\\$

(Right tailed test)

STd error assuming H0 to be true = $\sqrt{pq/n} =0.0144$ for n =1200

Mean difference =0.02

Test statistic =1.386

p value = 0.0823

5) If n =2500, std error would be = 0.01

Test statistic Z = 2

p value = 0.25

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3 years ago

HELP!!! THIS IS A MISSING ASSIGNMENT IF I GET THIS WRONG I FAIL THE ASSIGNMENT:(

Marianna [84]

Answer:

I think A.

Step-by-step explanation:

yes

8 0

3 years ago

Read 2 more answers

What is a triangle with at least two congruent sides and two congruent angles

pochemuha

Answer:

isosceles triangle

Step-by-step explanation: an isosceles triangle has 2 congruent sides, and 2 congruent angles

7 0

3 years ago

A mile is 5280 feet.

alekssr [168]

Answer:

10408 ft

Step-by-step explanation:

convert miles to ft

4 miles/hr * 5280 ft/ mile = 21120 ft/hr

convert hr to min

21120 ft/hr * 1hr/60 min = 352 ft/ min

multiply by 40 minutes

352 ft/min * 40 min =14080 ft

7 0

3 years ago

5^(-x)+7=2x+4 This was on plato

Setler79 [48]

Answer:

Below

I hope its not too complicated

$x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

Step-by-step explanation:

$5^{\left(-x\right)}+7=2x+4\\\\\mathrm{Prepare}\:5^{\left(-x\right)}+7=2x+4\:\mathrm{for\:Lambert\:form}:\quad 1=\left(2x-3\right)e^{\ln \left(5\right)x}\\\\\mathrm{Rewrite\:the\:equation\:with\:}\\\left(x-\frac{3}{2}\right)\ln \left(5\right)=u\mathrm{\:and\:}x=\frac{u}{\ln \left(5\right)}+\frac{3}{2}\\\\1=\left(2\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)-3\right)e^{\ln \left(5\right)\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)}$

$Simplify\\\\\mathrm{Rewrite}\:1=\frac{2e^{u+\frac{3}{2}\ln \left(5\right)}u}{\ln \left(5\right)}\:\\\\\mathrm{in\:Lambert\:form}:\quad \frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}$

$\mathrm{Solve\:}\:\frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}:\quad u=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)\\\\\mathrm{Substitute\:back}\:u=\left(x-\frac{3}{2}\right)\ln \left(5\right),\:\mathrm{solve\:for}\:x$

$\mathrm{Solve\:}\:\left(x-\frac{3}{2}\right)\ln \left(5\right)=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right):\\\quad x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

3 0

3 years ago