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Helga [31]
1 year ago
3

(3x869)+(19x528)+428(3)(1049)=a a=

Mathematics
1 answer:
Dima020 [189]1 year ago
7 0

The value of a in the equation (3x869)+(19x528)+428(3)(1049)=a is 1359555

<h3>How to evaluate the expression?</h3>

From the question, the equation to evaluate is given as

(3x869)+(19x528)+428(3)(1049)=a

Rewrite the above equation to make it legible

So, we have the following equation

(3 x 869) + (19 x 528) + 428(3)(1049) = a

Evaluate the products in the expression

So, we have the following equation

2607 + (19 x 528) + 428(3)(1049) = a

Evaluate the other products in the expression

So, we have

2607 + 10032 + 428(3)(1049) = a

Remove the brackets in the equation

So, we have the following equation

2607 + 10032 + 1346916 = a

Evaluate the sum

1359555 = a

Rewrite as

a = 1359555

Hence, the solution to the equation is 1359555

Read more about equations at

brainly.com/question/21405634

#SPJ1

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