Write an equation of the line that passes through (-4,1) and is perpendicular to the
1 answer:
Answer:
line1:y=2x+3
Gradient1=2
Let line2 be the line passes through (-4,1)and perpendicular to line1.
Because line2 and line1 are perpendicular, (gradient of line2) (gradient of line1) =-1
Gradient of line2=-1/2
Equation of line2:y-y1 =m(x-x1)
:y-1 =(-1/2)[x-(-4)]
:(y-1)(-2)=(x+4)
:-2y+2 =x+4
:-2y+2-x-4=0
:-x-2y-2 =0
:x+2y+2 =0
*notes:gradient=m
You might be interested in
Step-by-step explanation:
ans is $351.271875 of total cost
Answer:
rectangle hope it helpss
Answer:
15
Step-by-step explanation:
googled it
(-2,-8) is what I got after reflecting it off the y=x line.
The vertex of the equation is ( -2 , -2 )
The axis of symmetry is x= - 2
