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CaHeK987 [17]
3 years ago
12

Write an equation of the line that passes through (-4,1) and is perpendicular to the

Mathematics
1 answer:
trasher [3.6K]3 years ago
3 0

Answer:

line1:y=2x+3

Gradient1=2

Let line2 be the line passes through (-4,1)and perpendicular to line1.

Because line2 and line1 are perpendicular, (gradient of line2) (gradient of line1) =-1

Gradient of line2=-1/2

Equation of line2:y-y1 =m(x-x1)

:y-1 =(-1/2)[x-(-4)]

:(y-1)(-2)=(x+4)

:-2y+2 =x+4

:-2y+2-x-4=0

:-x-2y-2 =0

:x+2y+2 =0

*notes:gradient=m

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Given parameters:

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                   = \frac{3 + 19}{2}  , \frac{4 + 16}{2}

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