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2 years ago

The curved urface area of a cone i 140π cm2. What will be the radiu of a cone whoe lant height i 5 cm

Mathematics

1 answer:

VashaNatasha [74]2 years ago

7 0

The radius of a cone with a curved surface area of 140π cm² and a slant height of 5 cm will be 28 cm.

<h3>What is curved surface area?</h3>

The region with just curved surfaces, leaving the circular top and base, is referred to as the curved surface area. Total Surface Area is the combined area of the bases and the curved surface. The measurement of a solid's curved surface area is its outer area, which excludes the top and bottom extensions. Surface area of the cylinder that is curved: A right circular cylinder is the solid that results when a rectangle circles around one side and makes a full revolution. The curved surface area of a cylinder (CSA) is also known as the lateral surface area and is defined as the area of the curved surface of any given cylinder having a base radius "r" and height "h".

Here,

Curved surface area of cone=πrl

=140π

l=5 cm

140π=πr*5

r=140/5

r=28 cm

The radius of cone that has 5 cm as slant height and 140π cm² as the curved surface area will be 28 cm.

To know more about curved surface area,

brainly.com/question/1037971

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If the Base Diameter = Height of the Cone

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Therefore,

$\text{Volume of the cone}=\dfrac{\pi h}{3} (\dfrac{h}{2}) ^2 \\V=\dfrac{\pi h^3}{12}$

Rate of Change of the Volume, $\dfrac{dV}{dt}=\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}$

Since gravel is being dumped from a conveyor belt at a rate of 10 cubic feet per minute. Therefore, the Volume of the cone is increasing at a rate of 10 cubic feet per minute.

$\dfrac{dV}{dt}=10$ ft^3/min$

We want to determine how fast is the height of the pile is increasing when the pile is 24 feet high.

We have:

$\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}=10\\\\$When h=24$ feet$\\\dfrac{3\pi *24^2}{12}\dfrac{dh}{dt}=10\\144\pi \dfrac{dh}{dt}=10\\ \dfrac{dh}{dt}= \dfrac{10}{144\pi}\\ \dfrac{dh}{dt}=0.0221$ feet per minute$

When the pile is 24 feet high, the height of the pile is increasing at a rate of 0.0221 feet per minute.

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