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Musya8 [376]
1 year ago
12

Caden states that n^2 +3n + 2n is an equivalent expression to 6n. Why is Caden's statement incorrect?

Mathematics
1 answer:
malfutka [58]1 year ago
7 0
\begin{gathered} \text{The simplification of n}^2+3n+2n\text{ is:} \\ i)n^2+5n \\ By\text{ collecting common term, this can be written in form of:} \\ ii)\text{ n(n+5)} \end{gathered}

Thus, options A and D hold, from the simplifications above.

Let's consider the validity of the remaining options provided.

\begin{gathered} \text{For option B)} \\ \text{substitute for n=1 into the expression n}^2+3n+2n,\text{ we have} \\ 1^2+3(1)+2(1)=1+3+2=6 \\ \text{substitute for n=1 into the expression 6n, we have} \\ 6(1)=6 \\ \text{Thus, the expression n}^2+3n+2n\text{ is equivalent to 6n, for n=1} \end{gathered}\begin{gathered} \text{For option C)} \\ \text{The expression n}^2+3n+2n\text{ does not simplify to 7n} \end{gathered}\begin{gathered} \text{For option E)} \\ \text{substitute for n=4 into the expression n}^2+3n+2n,\text{ we have:} \\ 4^2+3(4)+2(4)=16+12+8=36 \\ \text{substitute for n=6 into the expression 6n, we have:} \\ 6(4)=24 \\ \text{Thus, the two(2) expressions are not equivalent to each other, for n=4} \end{gathered}\begin{gathered} \text{For option F)} \\ \text{substitute for n=3 into the expression n}^2+3n+2n,\text{ we have:} \\ 3^2+3(3)+2(3)=9+9+6=24 \\ \text{substitute for n=3 into the expression 6n, we have:} \\ 6(3)=18 \\ \text{Thus, the two(2) expressions are not equivalent to each other, for n=3} \end{gathered}

Hence, the correct options that apply are options A, D, E and F

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8 OR -8 OR Both

Step-by-step explanation:

-2 x 4 = -8

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6 0
3 years ago
Select all input values for which g(x)=8
Naily [24]

Answer:

a. x = -4

c. x = 9

Step-by-step explanation:

Values of g(x), output values, are plotted on the y-axis, while the corresponding x values, input, of the function are plotted on the x-axis.

We are to determine all possible input values (x-values) that will give us an output value, g(x) = 8.

On the graph, look at the point where y = 8, on the y-axis. When y = 8, we have two possible values of x. They are -4, and 9.

Thus:

g(-4) = 8

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The possible input values for which g(x) = 8, are x = -4, and x = 9.

8 0
3 years ago
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2 years ago
Rearrange the equation to isolate A.<br> H=K+log(A/C)
Xelga [282]

Answer:

A=C(10)^{H-K}

Step-by-step explanation:

The given equation is

H=K+\log(\frac{A}{C}

Subtract K to both sides of the equation

H-K=\log(\frac{A}{C}

Now, use the property, x=\log y\Rightarrow y=10^x

10^{H-K}=(\frac{A}{C}

Multiply both sides by C to isolate A

A=C(10)^{H-K}

The value of A is

A=C(10)^{H-K}

3 0
3 years ago
Read 2 more answers
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