Problem 1
x = measure of angle N
2x = measure of angle M, twice as large as N
3(2x) = 6x = measure of angle O, three times as large as M
The three angles add to 180 which is true of any triangle.
M+N+O = 180
x+2x+6x = 180
9x = 180
x = 180/9
x = 20 is the measure of angle N
Use this x value to find that 2x = 2*20 = 40 and 6x = 6*20 = 120 to represent the measures of angles M and O in that order.
<h3>Answers:</h3>
- Angle M = 40 degrees
- Angle N = 20 degrees
- Angle O = 120 degrees
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Problem 2
n = number of sides
S = sum of the interior angles of a polygon with n sides
S = 180(n-2)
2700 = 180(n-2)
n-2 = 2700/180
n-2 = 15
n = 15+2
n = 17
<h3>Answer: 17 sides</h3>
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Problem 3
x = smaller acute angle
3x = larger acute angle, three times as large
For any right triangle, the two acute angles always add to 90.
x+3x = 90
4x = 90
x = 90/4
x = 22.5
This leads to 3x = 3*22.5 = 67.5
<h3>Answers:</h3>
- Smaller acute angle = 22.5 degrees
- Larger acute angle = 67.5 degrees
Answer: 480
Step-by-step explanation:
8x6x10=480
48x10
480
Take the amount of rows in the auditorium, 15, and multiply that by the number of new seats in each row, 3. You get 45. Now multiply the number of new seats, 45, by the cost of each seat, $74. You get $3,330.
The length of the side = <span>The length of the arc intercepted by the central
<span>angle
</span></span>∴ length = Θ r
where Θ = <span>central<span> angle in radians
and r = radius
∴ </span></span><span>Θ = 70° = 70 * π /180
</span><span>r = 13 in.
∴ </span>length = <span>(70 * π /180) * 13 ≈ 15.88 in.
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