The answer to the question
Answer:
Step-by-step explanation:
A vector perpendicular to the plane ax+by+cz+d=0 is of the form .
So, a vector perpendicular to the plane x − y + 2z = 7 is .
The parametric equations of a line through the point and parallel to the vector are as follows:
Put and
Therefore,
xy-plane:
Put z = 0 ⇒ t = -2 ⇒x = - 1 , y = 6
So, at point (-1,6,0)
yz-plane:
Put x = 0 ⇒ t = -1 ⇒ y = 5, z =2
So, at point (0,5,2)
xz-plane:
Put y = 0 ⇒ t = 4 ⇒ x = 5, z = 12
So, at point (5,0,12)
3v=24
Simply divide 3 on both sides
Final Answer: v= 8
x=y/3-6
Step-by-step explanation:
<span>
-20 = 4a - 2b + c
-4 = c
-20 = 16a + 4b + c
4a - 2b + c = 16a + 4b + c
4a - 2b = 16a + 4b
-6b = 12a
b = -2a
-20 = 4a - 2b + c
-20 = 4a + 4a - 4
-16 = 8a
-2 = a
b = 4
c = -4
y = -2x^2 + 4x - 4
y = -2 * (x^2 - 2x) - 4
y = -2 * (x^2 - 2x + 1 - 1) - 4
y = -2 * (x^2 - 2x + 1) + 2 - 4
y = -2 * (x + 1)^2 - 2 </span>