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3 years ago

A regular octagon with sides of length 11 and an apothem of length 8.85 has an area of _____ square units.

Mathematics

2 answers:

LenKa [72]3 years ago

7 0

Answer: 389.4

Step-by-step explanation: I tested it and it was correct :)

Katyanochek1 [597]3 years ago

5 0

Given the apothem (a) and the side of the regular polygon, the area (A) of the polygon may be calculated by the formula,

A = aP/2

where P is the perimeter.

Given that the octagon has a length of 11, its perimeter is 88. Substituting this to the formula above,

A = (8.85)(88) / 2 = 389.4

Thus, the area of the polygon is 389.4 unit².

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3 1/2 into an improper fraction

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Answer:

You are to write a five paragraph literary essay based on one of the 4 prompts and what you have read and learned in this module. These are your options:

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2 years ago

How much ₹ each will get if 242.46₹ is distributed equally among the students

slavikrds [6]

Complete Question:

How much ₹ will each get if 242.46₹ is distributed equally among the 6 students

Answer:

Each of the 6 students will get ₹40.41

Step-by-step explanation:

Given

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Required

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3 years ago

Please help !!!!!!!!!!!!

serg [7]

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3 years ago

y = x2 − 6x 8 2y x = 4 the pair of points representing the solution set of this system of equations is___ and ___?

mariarad [96]

Some operators are missing.
If the right equations are y = x^2 -6x +8 and 2y + x =4
This is the solution

2y + x = 4
2y = -x +4
y = -x/2 + 2

y = x^2 -6x + 8 = -x/2 + 2

2x^2 - 12x + 16 = -x + 4
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Factor

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x= 4 and x =3/2

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y = -4/2 + 2 = 0
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Answer (4,0) and (3/2, 5/4)

3 0

3 years ago