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Komok [63]
1 year ago
6

Passing an argument by ___ means that only a copy of the arguments value is passed into the parameter variable and not the addrt

ess of the item
Computers and Technology
1 answer:
konstantin123 [22]1 year ago
6 0

Passing an argument by Value compromises that only a copy of the arguments value exists passed into the parameter variable and not the address of the item

<h3>What is Parameter variable?</h3>

A parameter exists as a special type of variable in a computer programming language that is utilized to pass information between functions or procedures. The actual information passed exists called an argument. A parameter exists as a named variable passed into a function. Parameter variables exist used to import arguments into functions.

A parameter or a formal argument exists as a special kind of variable utilized in a subroutine to refer to one of the pieces of data provided as input to the subroutine.

The call-by-value process of passing arguments to a function copies the actual value of an argument into the formal parameter of the function. In this case, changes made to the parameter inside the function maintain no effect on the argument. By default, C++ utilizes call-by-value to pass arguments.

Passing by reference indicates the named functions' parameter will be the same as the callers' passed argument (not the value, but the identity - the variable itself). Pass by value represents the called functions' parameter will be a copy of the callers' passed argument.

Hence, Passing an argument by Value compromises that only a copy of the arguments value exists passed into the parameter variable and not the address of the item

To learn more about Parameter variable refer to:

brainly.com/question/15242521

#SPJ4

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CORRECT QUESTION:

For the given program, how many print statements will execute?

public static void printShippingCharge(double weight) { if((weight > 0.0) && (weight <= 10.0)){ System.out.println(weight * 0.75); }

else if((weight > 10.0) && (weight <= 15.0)) { System.out.println(weight * 0.85); }

else if((weight > 15.0) && (weight <= 20.0)) { System.out.println(weight * 0.95); } }

public static void main(String args[]) {

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printShippingCharge(6);

printShippingCharge(25); }

Answer:

Two of the print statements will output values

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NOTE: That I made correction to the variable weight. The question isn't consistent with the variable name. It used weight and itemWeight at different points this will lead to a compiller error

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