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Reika [66]
3 years ago
14

Many company websites are now designed to do more than just sell a product. These​ websites, known as​ __________ websites, atte

mpt to build closer customer relationships and generate engagement with and between the brand and its customers.
Computers and Technology
1 answer:
Zinaida [17]3 years ago
5 0

Answer:

brand community

Explanation:

Many company websites are now designed to do more than just sell a product. These​ websites, known as​ brand community websites, attempt to build closer customer relationships and generate engagement with and between the brand and its customers. These online communities bring together consumers who have shared interests in a brand or product. One advantage of online brand communities is that they reduce customer support costs as the business has more engagement with their customers.This also helps the business to retain customers through brand improvement centered around the customer's actual needs.

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Tpy6a [65]
Either wiped off the drive, or right next to the new ones, I do not recommend keeping the old files.
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3 years ago
What is force? what are the types of force ? Explain all with suitable examples<br>​
ad-work [718]
Force is a push or pull which is exerted on an objects. Types of Force are

Contact forces
Non contact forces or At a distance forces

Examples of Contact forces are:
Stretching of the spring of a balance
pushing of a pram
kicking of a football
Pushing the door
Hitting the ball etc are some examples of contact forces.

some types of contact forces are given in the list below:

Applied force
Normal force
Frictional force
Tension force
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3 years ago
If a user's input string matches a known text message abbreviation, output the unabbreviated form, else output: Unknown. Support
Molodets [167]

Answer:

Here is the JAVA program. I  have added a few more abbreviations apart from LOL and IDK.

import java.util.Scanner; // to take input from user

public class MessageAbbreviation {

public static void main(String[] args) { //start of main() function body

   Scanner input = new Scanner(System.in); // create object of Scanner

       String abbreviation= ""; //stores the text message abbreviation

/* In the following lines the abbreviation string type variables contain the un-abbreviated forms */

           String LOL = "laughing out loud";

           String IDK = "i don't know";

           String BFF = "best friends forever";

           String IMHO = "in my humble opinion";

           String TMI = "too much information";

           String TYT = "take your time";

           String IDC = "I don't care";

           String FYI = "for your information";

           String BTW = "by the way";

           String OMG = "oh my God";

//prompts the user to enter an abbreviation for example LOL

           System.out.println("Input an abbreviation:" + " ");

           if(input.hasNext()) { // reads the abbreviation form the user

           abbreviation= input.next(); }

// scans and reads the abbreviation from user in the abbreviation variable

/*switch statement checks the input abbreviation with the cases and prints the un abbreviated form in output accordingly. */

    switch(abbreviation) {

       case "LOL" : System.out.println(LOL);

                    break;

       case "IDK" : System.out.println(IDK);

                    break;

       case "BFF" : System.out.println(BFF);

                    break;

       case "IMHO": System.out.println(IMHO);

                     break;

       case "TMI": System.out.println(TMI);

                     break;

       case "TYT": System.out.println(TYT);

                     break;

       case "IDC": System.out.println(IDC);

                     break;

       case "FYI": System.out.println(FYI);

                     break;

       case "BTW": System.out.println(BTW);

                     break;

       case "OMG": System.out.println(OMG);

                     break;

                     

       default    : System.out.println("Unknown"); } } }

Explanation:

The program first prompts the user to enter an abbreviation. Lets say the user enters LOL. Now the switch statement has some cases which are the conditions that are checked against the input abbreviation. For example if the user enters LOL then the following statement is executed:

case "LOL" : System.out.println(LOL);

This means if the case is LOL then the message ( un abbreviated form) stored in the LOL variable is displayed on output screen So the output is laughing out loud.

Anything else entered other than the given abbreviations will display the message: Unknown

The output is attached as screen shot.

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One of the jobs of the webmaster are to create a website<br>true or false
Talja [164]

true is the correct answer

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Find and fix the error in the if-else statement. import java.util.Scanner;
salantis [7]

Answer:

Hi there Rumanruxi! The error is in the if statement "if(userNum = 2)".

Explanation:

The if statement in this Java code is assigning userNum the value of 2 instead of comparing it with the value of 2. For equals comparison we need to write two equals "==" in the statement as: "if (userNum == 2)". This will return true if userNum is 2 otherwise it will return false.  

3 0
3 years ago
Read 2 more answers
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