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sladkih [1.3K]
1 year ago
7

If y=kx, where k is a constant, and y=24 when x=6, what is the value of y when x=5?A. 6B. 15C. 20D. 23

Mathematics
1 answer:
Marizza181 [45]1 year ago
7 0

First, we will find the value of k

We can do this by sybstituting y=24, x=6 in;

y=kx and then solve for k

24= k(6)

divide both-side of the equation by 6

24/6 = k

4 = k

k=4

Then when x = 5, we will substitute x=5 and k=4 in; y=kx and then solve for y

y= (4)(5)

y = 20

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8 0
3 years ago
Fill in the blank for Remainder Therom<br><br><br> x 3 + x 2 - 21x - 45 = (x + 3)(x - 5)(x+?)
icang [17]
Not sure about remainder theorem but I'm sure that the last terms should all multiply tho the last term


see the expanded form is -45

so the last terms of each binomial should multiply to -45

3 times -5 times ?=-45
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divide by -15
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the question mark is 3
5 0
3 years ago
Read 2 more answers
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Advocard [28]
Answer:
c 108

Explanation:
r/6=18
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I hope this helps!
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