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topjm [15]
3 years ago
10

How would you put this expression in factored form? 4x2 + 11x + 6

Mathematics
2 answers:
Mice21 [21]3 years ago
8 0

Answer:

Its (4x+3)(x+2) 100%

Step-by-step explanation:


just olya [345]3 years ago
3 0

we have

4x^{2} +11x+6

Equate the expression to zero

4x^{2} +11x+6=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

4x^{2} +11x=-6

Factor the leading coefficient

4(x^{2} +(11x/4))=-6

Complete the square. Remember to balance the equation by adding the same constants to each side

4(x^{2} +(11x/4)+(121/64))=-6+(121/16)

4(x^{2} +(11x/4)+(121/64))=(25/16)

(x^{2} +(11x/4)+(121/64))=(25/64)

Rewrite as perfect squares

(x+(11/8))^{2}=(25/64)

Square root both sides

x+(11/8)=(+/-)\sqrt{\frac{25}{64}}

x=(-11/8)(+/-)\frac{5}{8}

x=(-11/8)+\frac{5}{8}=-\frac{6}{8}=-\frac{3}{4}

x=(-11/8)-\frac{5}{8}=-\frac{16}{8}=-2

therefore

4x^{2} +11x+6=4(x+\frac{3}{4})(x+2)=(4x+3)((x+2)

<u>the answer is</u>

(4x+3)((x+2)

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