Answer: Let c represents the time spends in producing a cockpit and p represents the time spends in producing a propulsion system. Thus, According to the question, Machine A ran for 26 hours and produced 4 cockpits and 6 propulsion systems.⇒ 4 c + 6 p = 26And, Machine B ran for 56 hours and produced 8 cockpits and 12 propulsion systems,⇒ 8 c + 12 p = 56Hence, the system of equations that will be used to find a unique amount of time that it takes each machine to produce a cockpit and to produce a propulsion system is,4 c + 6 p = 26, 8 c + 12 p = 56But both lines are parallel,Hence there is no solution of this system,Therefore, we can not solve for a unique amount of time that it takes each machine to produce a cockpit and to produce a propulsion system.
Answer:
A) 3(x+6)
Step-by-step explanation:
Given,
The area of the model = (6x+18)
If the dimensions of the model are, x unit × y unit,
Then,
xy = 6x + 18
If x = 3, y = x + 6
3(x+6) = 3x + 18 ( by distributive property )
∴ Option A doesn't represent the dimensions of the model,
If x = 6, y = x + 3
6(x+3) = 6x + 18
∴ Option B represents the dimensions of the model,
If x = 0.5, y = 12x+36
0.5(12x+36) = 6x + 18
∴ Option C represents the dimensions of the model,
If x = 0.25, y = 24x + 72
0.25(24x+72) = 6x+18
∴ Option D represents the dimensions of the model,
If you substitute 2 for x, and 3 for y, than that gives you half the value of the real answer. So 2×3 =6, what is 6 half of? 12
Option 3: EF, DE, FD is the right answer
Step-by-step explanation:
"The side opposite to the largest angle of a triangle is the largest and the side opposite to the shortest side is the shortest"
We will observe the given triangle according to the axiom stated above
So,
The largest angle in the given triangle is ∠D = 86°, so the side opposite to it, EF will be the largest
Smallest angle is ∠E = 44°, so the side opposite to it, side FD will be the shortest.
Hence,
The sides in order from longest to shortest will be:
EF, DE, FD
Option 3: EF, DE, FD is the right answer
Keywords: Triangles, Angles
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