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shusha [124]
3 years ago
8

2/3 x 4/5? or any other way of solving this

Mathematics
1 answer:
Kazeer [188]3 years ago
6 0
You have to make the bottoms numbers the same (15) 3x5=15 5x3=15 so the answer is 8/15
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I need all three answer for an assignment
AfilCa [17]
This is false... you can get an easy example: (-2) + (10) = 10 - 2 = 8
7 0
2 years ago
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SMART STUDENT PLEASE NEED GOOD MATH STUDENT​
tangare [24]

Answer:

Therefore 'x' is equal to 65.4°

Step-by-step explanation:

In Right Angle Triangle ABC

∠ B = 90°

AC = Hypotenuse = 12

CB = Adjacent Side = 5

To Find:

∠ C = x

Solution:

In Right Angle Triangle ABC Cosine Identity we have

\cos C = \frac{\textrm{side adjacent to angle C}}{Hypotenuse}\\

Substituting the values we get

\cos C = \dfrac{CB}{AC}=\dfrac{5}{12}

\angle C = \cos^{-1}(0.4166)=65.37=65.4\°

Therefore 'x' is equal to 65.4°

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If QN bisects PQR and N is THE midpoint of PR classifiy each triangle by its angles and sides
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2 years ago
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Karolina [17]

Answer:

can I get free points? pleaaasee?

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2 years ago
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In the given diagram abc is a right angle with DG CB segment AB is divided into four equal parts . The coordinates of point F ar
pickupchik [31]

Answer:

E(3.75,-2.5)

G(-0.75,-3)

Step-by-step explanation:

Point E is the midpoint of the segment AB, then it has coordinates

\left(\dfrac{-3+6}{2},\dfrac{-1+(-3)}{2}\right)=\left(\dfrac{3}{2},-2\right).

Point F is the midpoint of the segment EB, then it has coordinates

\left(\dfrac{\frac{3}{2}+6}{2},\dfrac{-2+(-3)}{2}\right)=\left(\dfrac{15}{4},-\dfrac{5}{2}\right)=(3.75,-2.5).

Let S be the midpoint of segment CB, then it has coordinates

\left(\dfrac{-3+6}{2},\dfrac{-3+(-3)}{2}\right)=\left(\dfrac{3}{2},-3\right).

Point G is the midpoint of segment CS, then its coordinates are

\left(\dfrac{\frac{3}{2}+(-3)}{2},\dfrac{-3+(-3)}{2}\right)=\left(-\dfrac{3}{4},-3\right)=(-0.75,-3).

6 0
3 years ago
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