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Brut [27]
1 year ago
12

Please help me, it's due today!

Mathematics
2 answers:
Dima020 [189]1 year ago
5 0
Answer: -123
Step-by-step explanation:
-6(-4)^2+8(-4)+5
-6(-4)^2 iS -96
-96+8(-4) iS -128
-128+5 iS -123
m_a_m_a [10]1 year ago
4 0

Answer:

I believe it is -123

Step-by-step explanation:

you have to replace all the x's with -4 so you would do the equation -6(-4)^2+8(-4)+5

-6(-4)^2 is -96

-96+8(-4) is -128

-128+5 is -123

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Dennis_Churaev [7]
4*5 is 20
add 2 zeroes to the end because of the two you took out from 40 and 50
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4 years ago
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Assume there are 10 people in a room, including you. each person in the room must shake hands one time, and only one time, with
Dvinal [7]
You calculate the number of ways that 2 people can be chosen from 10.
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Source:
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4 0
3 years ago
Assume that 140 surveys are completed. Of those surveyed, 71 responded positively to effectiveness, 60 responded positively to s
liraira [26]

Answer:

15

Step-by-step explanation:

Let n(T) denotes total surveys done i.e. n(T)=140

Let n(A) be the no. of responses to positively to effectiveness i.e. n(A)=71

Let n(B) be the no. of side effects i.e.n(B) =60

Let n(C) be the no. of responses to cost i.e. n(C)= 65

33 responded positively to both effectiveness and side effects

So, n(A∩B)=33

31 to effectiveness and cost

n(A∩C)=31

28 to side effects and cost

n(B∩C)=28

21 to none of the items

So, n(A∪B∪C)=140-21 = 119

we are supposed to find ow many responded positively to all three i.e. n(A∩B∩C)

Formula:

n(A∪B∪C)=n(A)+n(B)+n(C)-n(A∩B)-n(A∩C)-n(B∩C)+ n(A∪B∪C)

119=71+60+65-33-31-28+ n(A∪B∪C)

119=104+ n(A∪B∪C)

119-104= n(A∪B∪C)

15= n(A∪B∪C)

Hence 15 responded positively to all three

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Answer:

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if your adding more stuff to your shopping cart it does not matter what item it is it will always increase  

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What is 672 divided by 12?
gregori [183]

Answer:

56

Step-by-step explanation:

7 0
3 years ago
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