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Tom [10]
3 years ago
11

If f(x) = 2x – 1and g(x) = x², Find fºg

Mathematics
1 answer:
morpeh [17]3 years ago
5 0

Answer: the answer is

Step-by-step explanation:

put g of x in f of x

(2x)^2 - 1

=4x^2 - 1

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What are opposite sides that are parallel
son4ous [18]

Answer: parallel means 2 sides that will never intersect

Step-by-step explanation:

5 0
3 years ago
If x/5+6=-14 then x equals
yanalaym [24]

Answer:

x = - 100

Step-by-step explanation:

Given

\frac{x}{5} + 6 = - 14 ( subtract 6 from both sides )

\frac{x}{5} = - 20

Multiply both sides by 5 to clear the fraction

x = 5 × - 20 = - 100

7 0
3 years ago
A high school had 2,300 students in 2010 which increased by 33% in the following four years. How many students are there in 2014
mr Goodwill [35]
Students in 2014 = (100% + 33%) × 2,300
students in 2014 = 133% × 2,300
students in 2014 = 133/100 × 2,300
students in 2014 = 3,059

There are 3,059 students in 2014
4 0
4 years ago
Rockwell hardness of pins of a certain type is known to have a mean value of 50 and a standard deviation of 1.2.a. If the distri
zalisa [80]

Answer:

a

 P(\= X \ge 51 ) =0.0062

b

P(\= X \ge 51 ) = 0

Step-by-step explanation:

From the question we are told that

The mean value is \mu = 50

The standard deviation is  \sigma = 1.2

Considering question a

The sample size is  n = 9

Generally the standard error of the mean is mathematically represented as

      \sigma_x = \frac{\sigma }{\sqrt{n} }

=>   \sigma_x = \frac{ 1.2 }{\sqrt{9} }

=>  \sigma_x = 0.4

Generally the probability that the sample mean hardness for a random sample of 9 pins is at least 51 is mathematically represented as

      P(\= X \ge 51 ) = P( \frac{\= X - \mu }{\sigma_{x}}  \ge \frac{51 - 50 }{0.4 } )

\frac{\= X -\mu}{\sigma }  =  Z (The  \ standardized \  value\  of  \ \= X )

     P(\= X \ge 51 ) = P( Z  \ge 2.5 )

=>   P(\= X \ge 51 ) =1-  P( Z  < 2.5 )

From the z table  the area under the normal curve to the left corresponding to  2.5  is

    P( Z  < 2.5 ) = 0.99379

=> P(\= X \ge 51 ) =1-0.99379

=> P(\= X \ge 51 ) =0.0062

Considering question b

The sample size is  n = 40

   Generally the standard error of the mean is mathematically represented as

      \sigma_x = \frac{\sigma }{\sqrt{n} }

=>   \sigma_x = \frac{ 1.2 }{\sqrt{40} }

=>  \sigma_x = 0.1897

Generally the (approximate) probability that the sample mean hardness for a random sample of 40 pins is at least 51 is mathematically represented as  

       P(\= X \ge 51 ) = P( \frac{\= X - \mu }{\sigma_x}  \ge \frac{51 - 50 }{0.1897 } )

=> P(\= X \ge 51 ) = P(Z  \ge 5.2715  )

=>  P(\= X \ge 51 ) = 1- P(Z < 5.2715  )

From the z table  the area under the normal curve to the left corresponding to  5.2715 and

=>  P(Z < 5.2715  ) = 1

So

   P(\= X \ge 51 ) = 1- 1

=> P(\= X \ge 51 ) = 0

5 0
3 years ago
Which of the following relations is a function?
Y_Kistochka [10]
I dont know if this is multiple choice but A and D are functions
6 0
3 years ago
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